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Ivanshal [37]
3 years ago
5

25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]

Mathematics
1 answer:
masha68 [24]3 years ago
6 0
25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]  \\ 25-[2+5y-3y-6]=-6y+15-[5y-5-3y+3] \\ 25-2-5y+3y+6=-6y+15-5y+5+3y-3 \\ -2y+29=-8y+17 \\ 6y+29=17 \\ 6y=-12 \\ y=-2
Hope this helped :)
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