25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3]

1 answer:

6 0

$25-[2+5y-3(y+2)]=-3(2y-5)-[5(y-1)-3y+3] \\ 25-[2+5y-3y-6]=-6y+15-[5y-5-3y+3] \\ 25-2-5y+3y+6=-6y+15-5y+5+3y-3 \\ -2y+29=-8y+17 \\ 6y+29=17 \\ 6y=-12 \\ y=-2$
Hope this helped :)

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