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3 years ago

Hey guys I needed a help Solve 2x -3/x=1

Mathematics

1 answer:

pishuonlain [190]3 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

Given

2x - $\frac{3}{x}$ = 1

Multiply through by x

2x² - 3 = x ( subtract x from both sides )

2x² - x - 3 = 0 ← in standard form

To factorise the quadratic

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term.

The factors are + 2 and - 3

product = 2 × - 3 = - 6 and sum = 2 - 3 = - 1

Use these factors to split the x- term

2x² + 2x - 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x + 1) - 3(x + 1) = 0 ← factor out (x + 1) from each term

(x + 1)(2x - 3) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

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This should be some simple math with some steps but i really need help beause i dont understand the problems

olga nikolaevna [1]

I don’t understand it either

6 0

3 years ago

Work out the question below

Andrews [41]

Answer:

he needs 20.25 bags of sand and it would cost her 80.79

Step-by-step explanation:

150cm*90cm*15cm=202,500cm^3 this is how much sand she needs to fill it

202,500cm^3/10,000cm^3=20.25 this is how many bags he needs

3.99*20.25=80.79 this is how much it'll cost him for all 20.25 bags

6 0

2 years ago

Which number does NOT represent an integer? A. 3 B. 20.1 C. -10 D. 20/4

guapka [62]

Answer:

the number doesnt represent an integer?

A. 3

B. 20.1

C. -10

D. 20/4

Step-by-step explanation:

We call integers the “counting numbers, their negatives and zero”. I.e. 0,1,−1,2,−2,3,−3,.. etc.

non-integers means “everything except integers”. Which is not well-defined (i.e. nonsense). Why? Because nobody said what “everything” is.

Therefore, when somebody says “non-integer” he has to specify how he defines “everything”. In this case, our “everything” is probably “real numbers”.

Real numbers have an interesting definition concerning an abstract mathematical object called “field” . Let’s forget about that and let’s focus on a high school definition: Real numbers are probably all the numbers you know. They are those represented by a decimal and their negatives e.g. 345.232… and −243.13242240… where there are “infinitely many” digits at the end. Note that 2.5 is also a real number. Integers are too. Basically, real numbers are the numbers used to measure distances and their negatives.

To summirize, your answer is the following:

“non integers” means everything except the integers, where everything is defined however we want. The most common definition of everything in this case is “real numbers” and therefore the most common interpretation of “non integers” is “reals which are not integers”.

Examples of “reals which are not integers”: 1.5,2.88,1.3333… etc

the answer is

B. 20.1

6 0

3 years ago

A new dental bondlng agent. When bonding teeth, orthodontists must maintain a dry field. A new bonding adhesive(called "Smartbon

Gemiola [76]

Answer:

(a) H₀: μ ≥ 5.70 vs. Hₐ:μ < 5.70

(b) The rejection region is (t₀.₀₁,₉ ≤ -2.821).

(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(a)

The hypothesis is:

H₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. μ ≥ 5.70.

Hₐ: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. μ < 5.70.

(b)

The alternate hypothesis indicates that the hypothesis test is left-tailed.

The rejection region for the left tailed test will be towards the lower tail of the t-distribution curve.

The significance level of the test is: α = 0.01.

The critical value is:

$t_{\alpha ,(n-1)}=t_{0.01,(10-1)}=t_{0.01,9}$

Use the t-table for the critical value.

$t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821$

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (t₀.₀₁,₉ ≤ -2.821).

(c)

The test statistic value is:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}$

Given:

$\bar x=5.07\\s=0.46\\n=10\\\mu=5.70$

Compute the value of the t-statistic as follows:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{5.07-5.70}{0.46/\sqrt{10}} =-4.33$

The value of the test statistic is -4.33.

(d)

The value of the test is less than the critical value.

$t=-4.33$

This implies that the test statistic lies in the rejection region.

Hence the null hypothesis will be rejected at 1% significance level.

Conclusion:

As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(e)

The conditions required for the t-test for single mean to be valid is:

The data should be continuous.
The parent population should be normally distributed.
The sample should be randomly selected.

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3 years ago

I give brainlist

olga nikolaevna [1]

False, It was till Pack 5 it was going up 3 every pack but at 5 it went up 13 cookies.

4 0

3 years ago

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