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maksim [4K]
2 years ago
6

Which expression represents the prime factorization of 108?

Mathematics
1 answer:
ankoles [38]2 years ago
4 0

Answer:

2×2×3×3×3

Step-by-step explanation:

●108=

•2×54

•2×27

•3×9

• 3×3

Writing the prime numbers;

108=2×2×3×3×3

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7/7q+21= x /5q^2-45 then x=?​
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Answer:

x = 5q - 15

Step-by-step explanation:

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3 0
2 years ago
Can someone help me please?
kati45 [8]

Answer:

4/9

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator

GCD of 16 and 36 is 4

Divide both the numerator and denominator by the GCD

16 ÷ 4

36 ÷ 4

Reduced fraction:  

4

9

Therefore, 16/36 simplified to lowest terms is 4/9.

4 0
3 years ago
Read 2 more answers
At one store, 20 percent of the pairs of shoes sold are of men's athletic shoes. Lionel rings up 8 orders which contain one or m
PIT_PIT [208]
B Explanation
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7 0
3 years ago
Suppose that prior to conducting a coin-flipping experiment, we suspect that the coin is fair. How many times would we have to f
BabaBlast [244]

Answer:

153 times

Step-by-step explanation:

We have to flip the coin in order to obtain a 95.8% confidence interval of width of at most .14

Width = 0.14

ME = \frac{width}{2}

ME = \frac{0.14}{2}

ME = 0.07

ME\geq z \times \sqrt{\frac{\widecap{p}(1-\widecap{p})}{n}}

use p = 0.5

z at 95.8% is 1.727(using calculator)

0.07 \geq 1.727 \times \sqrt{\frac{0.5(1-0.5)}{n}}

\frac{0.07}{1.727}\geq sqrt{\frac{0.5(1-0.5)}{n}}

(\frac{0.07}{1.727})^2 \geq \frac{0.5(1-0.5)}{n}

n \geq \frac{0.5(1-0.5)}{(\frac{0.07}{1.727})^2}

n \geq 152.169

So, Option B is true

Hence  we have to flip 153 times the coin in order to obtain a 95.8% confidence interval of width of at most .14 for the probability of flipping a head

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2 years ago
A dilation changes the size AND the shape of a figure
dolphi86 [110]
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