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Anna [14]
3 years ago
15

A rectangle has a width of 59 centimeters and a perimeter of 238 centimeters. What is the rectangle's length?

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

60 cm

Step-by-step explanation:

2x the width and 2x the length gives you the perimeter. This can be represented by the equation:

2w + 2L = P

Use the information given in the word problem to fill in the variables.

2(59) + 2L = 238

118 + 2L = 238

move 118 to the other side of the equation.

2L = 238 - 118

2L = 120

move 2 to the other side of the equation.

L = \frac{120}{2}

L = 60

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Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

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so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

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so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

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\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

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\mathrm{Apply\:rule}\:\frac{a}{1}=a

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Therefore

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