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3 years ago

I need help with number 5

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Look at intersecting points of line on x- and y-axis.

The points would be: (8,0) & (0,4)

formula of slope = (y2-y1) / (x2-x1)

(4-0)/(0-8) = -4/8 = -1/2.

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Show Your Work! Will Mark Brainliest!

Nikolay [14]

Answer:

x= -4

Step-by-step explanation:

6 0

3 years ago

The temperature has been going down at a constant rate.In 4 hours it went down 12 degrees.Which expression best shows the temper

fomenos

Answer:

t = t₀ - 3n

Step-by-step explanation:

Let t be the temperature and t₀ be the initial temperature of the day

Let n be the number of hours after the initial temperature ( t₀) was registered

Let -3 be the constant of change of temperature ( In 4 hours it went down 12 degrees)

Now, let's write down the expression that shows the temperature change each hour, this way:

t = t₀ - 3n

After 2 hours

t = t₀ - 3 * 2 = t₀ - 6

After 5 hours

t = t₀ - 3 * 5 = t₀ - 15

After 3 hours and 30 minutes

t = t₀ - 3 * 3.5 = t₀ - 10.5

5 0

3 years ago

Simplify the expression:

olga55 [171]

Answer:

The correct answer is 20x-1

5 0

3 years ago

Please help I literally don’t understand this at all

mel-nik [20]

Answer:

x=13 y=10 z=3 d) 260

Step-by-step explanation:

vertex angles are congruent so you can set them equal to each other and solve

and then a straight like adds up to 180 so 180-(7(x-3)+5y)= your missing angle and then that angles is congruent to its opposite so 2(5z+15)=60

8 0

3 years ago

Set up an equation and solve the following problem.

nordsb [41]

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, t = $\dfrac{\textrm d miles}{\textrm s miph}$

Or, t = $\dfrac{\textrm 210 miles}{\textrm s miph}$

For Kent

Time = $\dfrac{\textrm Distance}{\textrm Speed}$

So, T = $\dfrac{\textrm D miles}{\textrm S miph}$

Or, T = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

∵ Time taken by both is same

So, t = T

Or, $\dfrac{\textrm 210 miles}{\textrm s miph}$ = $\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}$

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴ s = $\dfrac{840}{20}$

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

8 0

3 years ago