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emmasim [6.3K]
3 years ago
5

Let g be the function defined by g(x)= -x^2+10x.

Mathematics
1 answer:
valentina_108 [34]3 years ago
3 0
Details Let g be the function defined by g(x) --2+10x. Find g(a + h), gl-a), glva), a + g(a), and TanApMath7 2.3.006.Mt. [3 gta+h)-a2an napion Cah)2+10(ath) g(a) [a+h)la+h) a+ ah anth ai2ah+h210a+1on -attiox g(-a)= ag(a) g(a) 3-8-F -162 8 g-8) -(-) +b 3. TanApMath7 2.3.0 Question Details Fib Let g be the function defined by 16 +6 if x < 8 g(x) 10)0 0- Vx-8 if x z 8. Find g(-8), g(0), g(8), and g(16). g-8) 4+6 2 2<8 g(0) g(8) 9(16) -8+b -2 223

But I can’t figure out the answer for some unknown reason sorry
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Luis solves the following system of equations by elimination. What is the value of s in the solution of the system? 11 33
-Dominant- [34]

Answer:

Step-by-step explanation:

ok so this is what you would do

5s+3t=30

-1(2s+3t=-3)

which will become

5s+3t=30

-2s-3t=3

which turns into

3s = 33, s=11

5 0
3 years ago
Read 2 more answers
A ticket to see your favorite baseball team costs ​37.26$. That price decreases by ​0.28$ for every game lost during the regular
galben [10]

The equation that represents the given situation is required.The cost of the ticket after L losses is a. Initial cost of the ticket = $49.64Price decrease per game lost = $0.41Number of games lost = LMoney lost after L losses is So, the cost of the ticket after L losses would be the initial cost of the ticket minus the money lost after L losses.The cost of the ticket after L losses is a. 

5 0
1 year ago
A scuba diver descends in the water at a rate of 23 1/2
Makovka662 [10]

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1 ft.

Given:

A scuba diver descends in the water at a rate of 23 1/2  feet per minute for 2.6 minutes.

A scuba diver ascends at a rate of 28 feet per minute for 2 minutes after seeing a big fish.

To find :

The scuba diver's position relative to sea level after the 4.6 minutes.

Solution:

Rate of a scuba diver descending in the water for 2.6 minutes = R _1

R_1= 23\frac{1}{2}ft/min=\frac{47}{2} ft/min

Distance covered by a scuba diver in 2.6 minutes = d_1

d_1=R_1\times 2.6min=\frac{47}{2} ft/min\times 2.6 min=61.1 ft

Rate of a scuba diver ascending for 2 minutes = R _2

R_2= 28ft/min

Distance covered by a scuba diver in 2 minutes = d_2

d_2=R_2\times 2min=28 ft/min\times 2 =56 ft

The position of scuba diver after 4.6 minutes relative to sea level:

d_1-d_2=61.1 ft-56 ft=5.1ft

The scuba diver's position relative to sea level after the 4.6 minutes is 5.1ft.

Learn more about ascending rate and descending rate here:

brainly.com/question/1477877?referrer=searchResults

brainly.com/question/1072871?referrer=searchResults

3 0
3 years ago
omar has 5 liters of water he divides the water evenly between 4 buckets. how many milliters does omar pour in each bucket
ArbitrLikvidat [17]

Answer:

1250 milliliters

Step-by-step explanation:

Omar has 5 liters of water. He divides evenly between 4 buckets.

5/4 = 1.25

He pours 1.25 liters in each bucket.

Convert 1.25 liters into milliters.

1.25 × 1000

1250 milliliters.

Omar pours 1250 milliliters in each bucket.

5 0
3 years ago
Determine the equation of the line passing through the point below having the corresponding
dusya [7]

Answer:

y=1/5x-4

Step-by-step explanation:

So, first we're gonna put this into point slope form, (y-y1)=m(x-x1), then we'll convert it. When you plug the numbers in, you get (y+9)=1/5(x+25)

Then, you simplify!

y= 1/5(x+25)-9

y=1/5x+5-9

y=1/5x-4

Hope this helped!

5 0
3 years ago
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