Answer:3/8
Step-by-step explanation:
The simplest form of
15
/40 is 3
/8
.
Steps to simplifying fractions
Find the GCD (or HCF) of numerator and denominator
GCD of 15 and 40 is 5
Divide both the numerator and denominator by the GCD
15 ÷ 5
40 ÷ 5
Reduced fraction:
3
/8
Therefore, 15/40 simplified to lowest terms is 3/8.
Answer:
D
Step-by-step explanation:
9514 1404 393
Answer:
(-8)(1) = -8
Step-by-step explanation:
The multiplicative identity element is 1. Multiplying by 1 does not change the value. This is illustrated by ...
(-8)(1) = -8
Answer: What table?
Step-by-step explanation:

is a complex number that satisfies
![\begin{cases}r\cos x=-3\\[1ex]r\sin x=4\\[1ex]r=\sqrt{(-3)^2+4^2}\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7Dr%5Ccos%20x%3D-3%5C%5C%5B1ex%5Dr%5Csin%20x%3D4%5C%5C%5B1ex%5Dr%3D%5Csqrt%7B%28-3%29%5E2%2B4%5E2%7D%5Cend%7Bcases%7D)
The last equation immediately tells you that

.
So you have
![\begin{cases}\cos x=-\dfrac35\\[1ex]\sin x=\dfrac45\end{cases}](https://tex.z-dn.net/?f=%5Cbegin%7Bcases%7D%5Ccos%20x%3D-%5Cdfrac35%5C%5C%5B1ex%5D%5Csin%20x%3D%5Cdfrac45%5Cend%7Bcases%7D)
Dividing the second equation by the first, you end up with

Because the argument's cosine is negative and its sine is positive, you know that

. This is important to know because it's only the case that

whenever

. The inverse doesn't exist otherwise.
However, you can restrict the domain of the tangent function so that an inverse can be defined. By shifting the argument of tangent by

, we have

All this to say

So,

.