Question

Kristin wants to wrap a ribbon around the perimeter of a rectangle. The length is five less than twice the width. The perimeter is 56 inches. What are the dimensions?​

Answer 1

The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.

Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that

L = 2W - 5

Substituting L into P, we have

P = 2(2W - 5 + W)

P = 2(W - 5)

Since P = 56, we have

2(W - 5) = 56

~Dividing both sides by 2, we have

W - 5 = 56/2

W - 5 = 23

Adding 5 to both sides, we have

W = 23 + 5

W = 28 inches

Substituting W into L, we have

L = 2W - 5

L = 2(28) - 5

L = 56 - 5

L = 51 inches

So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

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