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german
3 years ago
7

Kristin wants to wrap a ribbon around the perimeter of a rectangle. The length is five less than twice the width. The perimeter

is 56 inches. What are the dimensions?​
Mathematics
1 answer:
romanna [79]3 years ago
5 0

The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.

Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that

L = 2W - 5

Substituting L into P, we have

P = 2(2W - 5 + W)

P = 2(W - 5)

Since P = 56, we have

2(W - 5) = 56

~Dividing both sides by 2, we have

W - 5 = 56/2

W - 5 = 23

Adding 5 to both sides, we have

W = 23 + 5

W = 28 inches

Substituting W into L, we have

L = 2W - 5

L = 2(28) - 5

L = 56 - 5

L = 51 inches

So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.

Learn more about perimeter of a rectangle here:

brainly.com/question/16715918

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Answer:

7.85 cm

Step-by-step explanation:

The circumference of a circle can be found using the following formula.

c=\pi d

The diameter is 2.5 centimeters. Therefore, we can substitute 2.5 cm in for d.

c=\pi *2.5 cm

Now, find the circumference.

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c=\pi *2.5 cm

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c= 2.5\pi  cm

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c=\pi *2.5 cm

c=3.14 *2.5 cm

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c=\pi *2.5 cm

c=7.85398163 cm

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3 years ago
Can you help me please ​
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Answer:

log_372 = 3.8928

Step-by-step explanation:

Given

log_38 = 1.8928

Required

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We have:

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log_372 = log_38 +log_39

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Evaluate the exponents

log_372 = log_38 +2log_33

log_33 = 1.

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log_372 = log_38 + 2 * 1

log_372 = log_38 + 2

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186

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3/8

Step-by-step explanation:

75% or 0.75 is equivalent to 3/4

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The given equation is:
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