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viktelen [127]
3 years ago
6

Help me please!!! 100 points

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

ohlkkkk

Step-by-step explanation:

but give your questions first

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Darina [25.2K]
<span>The result is 2x^2 - 3x + 2 .</span>
4 0
3 years ago
Please help me!
Harman [31]

Answer:

The graph of g(x) is a vertical translation of f(x). Although both have the same x coordinates but different y coordinates.

The graph of g is a <u>vertical</u><em> </em>translation of the graph of f <u>12</u> units <u>downward</u>.

Step-by-step explanation:

The equation y=f(x)+k represents that when k is negative, the graph moves downward.

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2 years ago
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Which expression is equivalent to 18 1/5- (22 2/5) - (40 1/5)
Mekhanik [1.2K]

Answer: 18 1/5 + 22 2/5 + 40 1/5

Step-by-step explanation:

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8 0
3 years ago
Find f. f ″(x) = x^−2, x &gt; 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
Write a rule for the linear function in the table above. ( Hint: Use the formula y = mx + b )
Marta_Voda [28]
Y=5x-3


the slope is plus 5
so if 1 = 2
simply subtract 5 from two and you get -3
6 0
3 years ago
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