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viktelen [127]
3 years ago
6

Help me please!!! 100 points

Mathematics
1 answer:
Tju [1.3M]3 years ago
8 0

Answer:

ohlkkkk

Step-by-step explanation:

but give your questions first

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Which expression can be used to find the value of the expression below -4(5 + (-2)​
guapka [62]

Answer:

-12

Step-by-step explanation:

-4(5+(-2))=-4(5-2)=-4(3)=-12

6 0
3 years ago
Write an equation of the circle with center (7,4)<br> and diameter 10
cestrela7 [59]
Circles follow ghe equations
(x-h)^2 + (y-k)^2 =r^2
with center (h,k) and radius r
for this circle it would be
(x-7)^2 + (y-4)^2 = 100
7 0
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The temperature at 6:00 P.M. was 68°F. This was 5°F lower than the temperature at 3:00 P.M. The temperature at 1:00 P.M. on that
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76 degrees Fahrenheit
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Is (2, 3) a solution to this system of equations?<br> 2x + y = 7<br> 17x + 19y = 18<br> yes<br> no
netineya [11]

I think its not a correct solution of given equations.

4 0
3 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
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