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2 years ago

8

In oak valley the cost of gas averaged $3.50 per gallon qt the start of April the rose 6% during April and dropped 10% during Ma

y. What was the cost of a gallon of gas at the end of May?

1 answer:

andreev551 [17]2 years ago

8 0

Answer:

$ 3.34

Step-by-step explanation:

3.50 * 1.06 cost at end of April then find 90% of this to find end of May

3.50 * 1.06 * .9 = $ 3.34

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1. You have $10 saved. Each week you receive $5 in allowance. Let x represent the number of weeks you

bazaltina [42]

That looks hard sorry I don’t know answer good luck

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2 years ago

Read 2 more answers

Sorry for all the pictures just help me pls

maksim [4K]

Answer:

i think the answer is the first picture

5 0

2 years ago

A vendor sells hotdogs and bags of potato chips .A customer buys 4 hot dogs and 4 bags of chips for $17.00 another customer buys

mario62 [17]

Let use h= hotdogs price and c=chips price
we know that
4h +4c= 17
5h+3c=17.75
t use the elimination method we will multiply the first equation by 5 and the second one by (-4)
20h +20c=85
-20h -12c= -71
8c=14, we will divide by 8 both side and c=1.75, so a bag of potato chips cost $ 1.75
now we will substitute the c in the first equation
4h+7=17 therefore 4h=17-7, 4h=10, h=2.50

a bag of potato chips is 1.75
a hot dog costs 2.50

7 0

3 years ago

A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take

muminat

Answer:

The speed of jogger in uphills is 4 mile per hour

And The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill (Du) = 2 miles

The time taken by jogger in downhill (Td) = T hour

The time taken by jogger in uphill (Tu) = T hour

Let The speed of jogger in uphills (Su) = x mph

So ,The speed of jogger in downhills (Sd) =( x + 6 ) mph

∵, Time = $\frac{Distance}{Speed}$

So, Tu = $\frac{Du}{Su}$

Or, T = $\frac{2}{x}$ h

And Td = $\frac{Dd}{Sd}$

Or, T = $\frac{5}{(x + 6)}$ h

∵ Time duration of both is same

∴ $\frac{2}{x}$ = $\frac{5}{(x + 6)}$

Or, 2 × (x + 6) = 5x

Or, 2x + 12 = 5x

So, 12 = 3x

∴ x = $\frac{12}{3}$ = 4 mph

And x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour

And The speed of jogger in downhills is 10 mile per hour Answer

5 0

3 years ago

Find the greatest common factor of the following mononmials : u^2v^2 , 11u^2v^5

weeeeeb [17]

Answer:

1

Step-by-step explanation:

Since there are no common prime factors, the only common factors for both monomials are 1, therfore they stay as they are, 11u²v⁵ and u²v².

I am joyous to assist you anytime.

3 0

3 years ago