Find all of the solutions for the following equation.

1) Twice a number decreased by four is 32.

LUCKY_DIMON [66]

Answer:

x = 18

Step-by-step explanation:

Twice a number becomes 2x, decreased by 4 becomes -4, and combined those terms equal 32.

2x - 4 = 32

2x - 4 + 4 = 32 + 4 (isolate the variable)

2x = 36

x = 18

3 0

3 years ago

.0000458 put this in scientific notation

amm1812

4.58 x 10^-5

hope I helped

3 0

3 years ago

Marco wants to buy a new smartphone that costs $495, with some additional accessories. He has already saved $75. Write and solve

Dennis_Churaev [7]

Answer:

495-75=m m=420

Step-by-step explanation:

He needs to save 495 dollars, and hes already saved 75

and needs to find out how much more he needs to save to have 495 dollars

To do this, take 495 and subtract 75. This is how we get the inequality

495-75=m

From here it is simple, just subtract 75 from 495 to get 420

3 0

2 years ago

-7 x (4+8) = ?? Please a aswer?

Colt1911 [192]

The answer would be -84.

Here are the steps I did.

1. Simplify 4 + 8 to 12 ( -7 * 12 )

2. Now lastly simplify and u get -84.

5 0

3 years ago

Read 2 more answers

Let D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} Determine which of the following statements are true and which are false. a)

morpeh [17]

Answer:

$\forall x\in D$ if x is odd then x> 0 is true statement.

$\forall x\in D$ if x is even then x≤0 is false statement.

$\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

$\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) $\forall x\in D$ if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

$\forall x\in D$ if x is odd then x> 0 is true statement.

Part (B) $\forall x\in D$ if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

$\forall x\in D$ if x is odd then x> 0 is true statement.

Part (C) $\forall x\in D$ if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

$\forall x\in D$ if x is even then x≤0 is false statement.

Part (D) $\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

$\forall x\in D$ If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) $\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

$\forall x\in D$ if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

8 0

3 years ago