Find all of the solutions for the following equation.

Which of these is a linear equation in standard form for the graph shown?

vampirchik [111]

Answer:

B

Step-by-step explanation:

Because the slope is a positive slope (goes through the positive quandrants on the graph), we can eliminate answer choices c. Now, if we solve a, b, and d and we can see if the slope + y-intercept matches the graph.

For A.) (solve for y to get a y=mx + b equation)

3x-2y=4

-2y= -3x + 4

y= 3/2 -2

For B.)

3x-2y= -4

-2y= -4-3x

y= 3/2 + 2

For D.)

2x+3y= 4

3y= 4-2x

y= -2/3x + 4/3

Now, if we look at D, the slope is negative so it cannot be D. That leaves us with A and B. The b in the y=mx + b equation stands for the y-intercept, so we can see that the y-intercept is 2. So, since the graph intersects the y-axis at (0,2), the answer is B! y=3/2 + 2 has a positive slope and 2 for the y-intercept!

4 0

3 years ago

How many sets of three consecutive integers are there in which the sum of the three integers equals their product?

skad [1K]

Answer:

3

Step-by-step explanation:

since the 3 integers are consecutive, we are dealing with x, x+1, x+2.

and their sum is the same as their product :

x + (x + 1) + (x + 2) = x(x + 1)(x + 2)

3x + 3 = x(x² + 3x + 2) = x³ + 3x² + 2x

x³ + 3x² - x - 3 = 0

this is a polynomial of third degree.

and as such it has 3 solutions.

of course, it could be that some of them are the same or are even in the realm of complex numbers (i = sqrt(-1)), but usually these 3 solutions are different real numbers.

I tried x=1 just to see, and, hey, it is a solution for this equation.

x = 1 means that the other 2 consecutive integers are 2 and 3.

and indeed, 1+2+3 = 1×2×3 = 6.

now it is easier to find the other 2 solutions, as a zero solution can be expressed as a factor of the whole expression.

for x = 1 the factor term is (x - 1), as this term is then turning 0, when x = 1.

I can divide the main expression by this factor and then analyze the quotient about the other 2 solutions.

x³ + 3x² - x - 3 : x - 1 = x² + 4x + 3

- x³ - x²

----------------

0 4x² - x

- 4x² - 4x

-----------------------

0 + 3x - 3

- 3x - 3

---------------------------

0 0

so, the original expression can be written as

(x² + 4x + 3)(x - 1).

now we need to find the 2 zero solutions for x²+4x+3

the general solution to a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 4

c = 3

so,

x = (-4 ± sqrt(4² - 4×1×3))/(2×1) =

= (-4 ± sqrt(16 - 12))/2 = (-4 ± sqrt(4))/2 =

= (-4 ± 2)/2 = -2 ± 1

x1 = -2 + 1 = -1

x2 = -2 - 1 = -3

so, we have the additional solutions :

-1 0 1

-3 -2 -1

-1 + 0 + 1 = -1×0×1 = 0

-3 + -2 + -1 = -3×-2×-1 = -6

and there we have it fully proven :

there are 3 different sets of 3 consecutive integers with the same sum as product.

4 0

3 years ago

May someone please me

sergejj [24]

If you convert 62 kilograms to lbs it will give you 136.687 lbs

6 0

3 years ago

Read 2 more answers

Velida took out a 5/1 variable-rate mortgage for $150,000. The interest rate

Afina-wow [57]

Answer:

B

Step-by-step explanation:

The amortization period in months is:

30 years * 12 = 360 months

The monthly interest rate would be 5.25%/12 = 0.004375

The payment for monthly mortgage formula would be:

$E=\frac{C*r}{1-(1+r)^{-n}}$

Where

E is the monthly mortgage payment

C is the cost of mortgage, cost is $150,000

r is the monthly rate of interest, which is 0.004375

n is the period, in months, which is 360

Substituting, we get our answer:

$E=\frac{C*r}{1-(1+r)^{-n}}\\E=\frac{150,000*0.004375}{1-(1+0.004375)^{-360}}\\E=\frac{656.25}{1-(1.004375)^{-360}}\\E=\frac{656.25}{0.7923}\\E=828.31$