We know that one inch has 16.5 turns.
To know the number of turns in 2.5 inches of thread, we will simply do a cross multiplication as follows:
number of turns = (2.5 x 16.5) / 1 = 41.25 turns
Answer:
m∠C=28°, m∠A=62°, AC=34.1 units
Step-by-step explanation:
Given In ΔABC, m∠B = 90°, , and AB = 16 units. we have to find m∠A, m∠C, and AC.
As, cos(C)={15}/{17}
⇒ angle C=cos^{-1}(\frac{15}{17})=28.07^{\circ}\sim28^{\circ}
By angle sum property of triangle,
m∠A+m∠B+m∠C=180°
⇒ m∠A+90°+28°=180°
⇒ m∠A=62°
Now, we have to find the length of AC
sin 28^{\circ}=\frac{AB}{AC}
⇒ AC=\frac{16}{sin 28^{\circ}}=34.1units
The length of AC is 34.1 units
Answer:
it's going to be 4n so its going to be 4...
Step-by-step explanation:
When you write URGENT the Brainly cops think you may be taking a test.
y = ax² + c thru (-1,4) and (0,8)
Substituting in the coordinates of each point for x and y gives two equations:
4 = a (-1)² + c
8 = a (0²) + c = c
From the second one we see c=8. Substituting into the first one,
4= a + 8
a = 4-8 = -4
Answer: a=-4, c=8
Check:
f(x) = -4x² + 8
f(0) = 8, good
f(-1) = -4(1) + 8 = 4, good
<span>First thing you'll need to know is that the value for this equation is actually an approximation 'and' it is imaginary, so, one method is via brute force method.
You let f(y) equals to that equation, then, find the values for f(y) using values from y=-5 to 5, you just substitute the values in you'll get -393,-296,-225,... till when y=3 is f(y)=-9; y=4 is f(y)=48, so there is a change in </span><span>signs when 'y' went from y=3 to y=4, the answer is between 3 and 4, you can work out a little bit deeper using 3.1, 3.2... You get the point. The value is close to 3.1818...
The other method is using Newton's method, it is similar to this but with a twist because it involves differentiation, so </span>

<span> where 'n' is the number you approximate, like n=0,1,2... etc. f(y) would the equation, and f'(y) is the derivative of f(y), now what you'll need to do is substitute the 'n' values into 'y' to find the approximation.</span>