2x^2+20x = -38
2x^2 + 20x + 38 = 0
Divide both sides by 2.
x^2 + 10x + 19 = 0
The quadratic formula works very well here.
Let a = 1, b = 10 and c = 19
x = [-b +- sqrt{b^2 - 4ac}]/(2a)
Plug those values into the formula to find two answers for x.
One is negative and the other positive.
Good luck.
The range would be 14.
Explanation: you subtract the lowest and highest values in the set of data, which would be 1 and 15
Answer:555
Step-by-step explanation:
Answer:
4y^{2}+3y
Step-by-step explanation:
First you need to distribute the values.
(4y+3)(2y) Using the "Rainbow Method" to multiply the polynomials
You Should get
8y^{2}+6y
Since this is the area of the rectangle and we need to find the area of the shaded region you need to dived 8y^{2}+6y in half because the shaded region is half of the rectangle.
8y^{2}+6y/2
Doing this you will get
4y^{2}+3y