<span>The amount P as a function of t (in years) is given by
P(t) = P0 (1 + r/n)^(t n)
So if n = 4, and r = 0.02, and P0 = 1000, then
P(t) = 1000 (1 + 0.02/4)^(4 t) = 1000 (1 + 0.005)^(4 t)
At the end of the first quarter, t = 1/4, so
P(1/4) = $1000 (1.005)^(1) = $1005
At the end of the second quarter, t = 1/2 , therefore
P(1/2) = $1000 (1.005)^(2) = $1000 (1.010025) = $1010.03
At the end of the third quarter , t = 3/4, therefore
P(3/4) = $1000 (1.005)^(3) = $1000 (1.015075125) = $1015.08
At the end of the year, t = 4, therefore
P(1) = $1000 (1.005)^4 = $1000 (1.020150500625) = $1020.15
As for the second question, after the first period (quarter),
the formula becomes
P = P0 (1.005)^1 = 1.005 P0
which is choice A. </span>
Answer:
-6 and negative 1 with the bio
Step-by-step explanation:
(8x^2+2x+8)+(3x^3+7x+4)=
8x^2+2x+8+3x^3+7x+4
3x^3+8x^2+(2+7)x+12=
3x^3+8x^2+9x+12
Answer: Option A. 3x^3+8x^2+9x+12
Answer:
If I'm correct I think 4 is the polygon
