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3 years ago

Given the linear equation 6x-2=2x+12, find x HELPPP PLEASEEE ASAP!!! Processss!

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer:

x=3.5

Step-by-step explanation:

add 2 to each side to cancel out the -2

6x=2x+14

subtract 2x from each side

4x=14

divide by 4

x=3.5

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Put the fraction in least to greatest 1/5, 5/5 ,4/5

konstantin123 [22]

Answer:

1/5, 4/5, 5/5

Step-by-step explanation:

1/5 is 20%

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Ludmilka [50]

Answer:

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3 years ago

multiply (x-4) (2x+3) using the distributive property. select the answer choice showing the correct distribution

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Answer:

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Step-by-step explanation:

(x-4) (2x+3)

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Find the center and radius of x^2+y^2=9

riadik2000 [5.3K]

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3 years ago

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h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

$a=-2,\\ \\b=2,$

so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

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3 years ago