Answer: the dwarf tree grew by 3 inches.
the semi dwarf tree grew by 6 inches.
the full size tree grew by 18 inches.
Step-by-step explanation:
Let x represent how much the semi-dwarf lemon tree grew.
Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. This means that the amount by which the dwarf lemon tree grew is expressed as x/2
A full-size lemon tree grew three times as much as the semi-dwarf lemon. This means that the amount by which the full-size lemon tree grew is expressed as 3x
Together, the three trees grew 27 inches. This means that
x/2 + x + 3x = 27
Cross multiplying by 2, it becomes
x + 2x + 6x = 54
9x = 54
x = 54/9
x = 6 inches
The dwarf tree grew by 6/2 = 3 inches.
The full-size lemon tree grew by 3 × 6 = 18 inches
Answer:

Step-by-step explanation:
step 1
Find the measure of the arc DC
we know that
The inscribed angle measures half of the arc comprising
![m\angle DBC=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=m%5Cangle%20DBC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)
substitute the values
![60\°=\frac{1}{2}[arc\ DC]](https://tex.z-dn.net/?f=60%5C%C2%B0%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20DC%5D)


step 2
Find the measure of arc BC
we know that
----> because the diameter BD divide the circle into two equal parts
step 3
Find the measure of angle BDC
we know that
The inscribed angle measures half of the arc comprising
![m\angle BDC=\frac{1}{2}[arc\ BC]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20BC%5D)
substitute the values
![m\angle BDC=\frac{1}{2}[60\°]](https://tex.z-dn.net/?f=m%5Cangle%20BDC%3D%5Cfrac%7B1%7D%7B2%7D%5B60%5C%C2%B0%5D)

therefore
The triangle DBC is a right triangle ---> 60°-30°-90°
step 4
Find the measure of BC
we know that
In the right triangle DBC


substitute the values

The answer will be definitely be A don’t listen
2/9 = 0.2222(repeating)
I hope this helps :)