Answer:
17; 22; 27; 32
the terms increase by 5 each time
17 + 5 = 22 (the second term)
17 + 5 * 2 = 27 (third term)
So to get to the 52nd term, we have to add 5* 51 = 255 to 17
17 + 255 = 272
Step-by-step explanation:
Answer:

Step-by-step explanation:
From C-A, it goes from y=1 to y=5, so that 4 units
From A-B, it goes from x = -1 to x = 4, that is 5 units
Now, to find distance from B to C, we need to use the distance formula:

Where the variables are the respective points of B and C,
B (4,5) & C(-1,1)
So x_1 =4, y_1=5, x_2=-1, y_2=1
Plugging into the formula we get:

Summing it all (perimeter is sum of 3 sides):
Distance = 
3rd answer choice is right.
So, first let's change these numbers into decimal form:
3*0.1 + 4*0.01 + 8*0.001 ? 1.2
Multiply:
0.3 + 0.04 + 0.008 ? 1.2
0.348 < 1.2
One and two tenths is larger.
Hopefully this is what you're asking, as this question is unclear
Try this option:
1) if V(0;0) and x= -4, then common view of the required equiation is:
(y-k)²=4p(x-h), where focus is in (h-p;k), the vertex is in (h;k), the directrix is x=h+p, p<0 and y=k is simmetry axis;
2) if the V(0;0), then h=k=0 and the required equiation is:
y²=4px;
3) if the directrix equation is x=h+p, where h=0, then p= -4 (according to the condition the directrix equation is x= -4), then the required equation is:
y²= -16x
answer: y²= -16x
Answer:
Center
Step-by-step explanation:
A diameter is a line segment whose endpoints are on a circle. It is a special type of chord because it must contain the center of the circle.