In a longitudinal wave, the motion of the medium is parrellel to the direction of the wave.
Here I advice doing thought experiment and not remembering equations. By doing thought experiment you will write down equation by yourself.
Doing some work on a system means that system will "absorb" that energy. Here, system absorbs 1000J of energy. Now you are cooling system down by removing 500J of energy. That means that system will lose 500J of energy
All of that can be written as 1000 - 500 = 500 which means that after cooling your system has 500J left.
Total resistance will be R1 + R2.
And the formula will be I equals V over R.
V=5
I=?
R=6
I= 0,83 amps
Answer:
We cannot tell from the information given
Explanation:
Given;
mass of the box, m = 5 kg
first force, F₁ = 10 N
second force, F₂ = 5 N
(I) Assuming the two forces are acting horizontally in opposite direction, the resultant force on the box is calculated as;
∑Fx = 10 N - 5 N
= 5 N
Apply Newton's second law of motion;
∑Fx = ma
a = ∑Fx/m
a = 5 / 5
a = 1 m/s² in the direction of the 10 N force.
(II) Also, if the two forces are acting in the same direction, the resultant force is calculated as;
∑Fx = 10 N + 5 N
∑Fx = 15 N
a = 15 / 5
a = 3 m/s²
Therefore, the information given is not enough to determine the acceleration of the box.
Answer: The pressure that one experiences on the Mount Everest will be different from the one, in a classroom. It is because pressure and height are inversely proportional to each other. This means that as we move up, the height keeps on increasing but the pressure will keep on decreasing. This is the case that will be observed when one stands on the Mount Everest as the pressure is comparatively much lower there.
It is because as we move up, the amount of air molecules keeps on decreasing but all of the air molecules are concentrated on the lower part of the atmosphere or on the earth's surface.
Thus a person in a low altitude inside a classroom will experience high pressure and a person standing on the Mount Everest will experience low pressure.