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3 years ago

6

A light microscope allows for more magnification than electron microscope because it uses a beam of visible light. true false

1 answer:

Igoryamba3 years ago

4 0

False because light microscopes have low resolve and magnification.

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Which of the following does not lead to addiction?

zloy xaker [14]

Answer:

Obesity does not lead to addiction. Obesity is a weight condition characterized by a body.

Explanation:

5 0

3 years ago

How does the resultant displacement change as the angle between two vectors increases from 90° to 120°?

user100 [1]

The resultant displacement between the two vectors will increase.

The resultant of the two vectors is given by parallelogram law of vectors.

The parallelogram law of vector addition states that if two vectors are represented in magnitude and direction by the adjacent sides of a parallelogram, the diagonal of the parallelogram drawn from the point of intersection of the vectors represents the resultant vector in magnitude and direction.

The resultant of these vectors, say vector A, and B, is given as;

$R^2 = a^2 + b^2 -2ab.Cos (\theta )$

When;

θ = 90°

$R^2 = a^2 + b^2$

When;

θ = 120°

$R^2 = a^2 + b^2 + ab$

Thus, the resultant displacement between the two vectors will increase.

Learn more here: brainly.com/question/20885836

8 0

3 years ago

What would be the first thing you would do if your clothes caught fire while working in a laboratory? select one of the options

Ksivusya [100]

<span>c. run towards a source of water to extinguish the fire </span>

3 0

3 years ago

What graph shape is this what does the snap tell you

vekshin1

The picture is hard to see but if you still need help message me

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2 years ago

A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car

kogti [31]

Answer:

$t_1 = \frac{v_i}{a_i}$

$t_2 = \frac{v_i}{a_i}$

Δd = $v_it_1 = v_i^2/a_i$

Explanation:

As $v(t) = v_i + at$ , when the car is making full stop, $v(t_1) = 0$ . $a = -a_i$ . Therefore,

$0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}$

Apply the same formula above, with $v(t_2) = v_i$ and $a = a_i$ , and the car is starting from 0 speed, we have

$v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}$

As $s(t) = vt + \frac{at^2}{2}$ . After $t = t_1 + t_2$ , the car would have traveled a distance of

$s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}$

Hence $s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}$

As $t_1 = t_2$ we can simplify $s(t) = v_it_1$

After t time, the train would have traveled a distance of $s(t) = v_i(t_1 + t_2) = 2v_it_1$

Therefore, Δd would be $2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i$

8 0

3 years ago