Answer:
18.032m/s, 16.59m
Explanation:
Used to find the distance traveled
y=1/2gt^2, where y= vertical distance, g=acceleration due to gravity, and t=time
y=1/2*9.8*1.84^2
y=16.59m distance
Used to solve the final velocity before hitting the ground
vf=vo+at where vf=final velocity, vo=initial velocity, a=acceleeration, t=time
vf=0+9.8*1.84
vf=18.032m/s
Answer: they are high in all except fiber
Answer:
<em>the mass of one helium nucleus should be</em> <em>less than the mass of four hydrogen nuclei.</em>
Explanation:
Deep inside the core of the Sun, enough protons can collide into each other with enough speed that they stick together to form a helium nucleus and generate a tremendous amount of energy at the same time. This process is called nuclear fusion.
The mass-to-energy conversion is described by Einstein's famous equation:
E = mc2, or, in words, energy equals mass times the square of the velocity of light. Because the velocity of light is a very large number, this equation says that lots of energy can be gained from using up a modest amount of mass.
Photons In the proton-proton chain reaction, hydrogen nuclei are converted to helium nuclei through a number of intermediates. The reactions produce high-energy photons (gamma rays) that move through the "radiative layer" surrounding the core. This layer takes up 60 percent of the radius of the Sun. It takes a million years for energy to get through this layer into the "convective layer", because the photons are constantly intercepted, absorbed and re-emitted. In the core, the helium nuclei make up 62% of the mass (the rest is still hydrogen). The radiative and convective layers have about 72% hydrogen, 26% helium, and 2% heavier elements (by mass). The energy produced by fusion is then transported to the solar surface and emitted as light or ejected as high-energy particles.
(a) 
The relationship between frequency and wavelength of an electromagnetic wave is given by
where
is the speed of light
is the frequency
is the wavelength
In this problem, we are considering light with wavelength of
Substituting into the equation and re-arranging it, we can find the corresponding frequency:
(b) 
The period of a wave is equal to the reciprocal of the frequency:
And using 
as we found in the previous part, we can find the period of this wave:
Bonjour
C'est la fille de ma mère mais ce n'est pas moi, qui est-ce ?
<em>She is my mother daughter but, she's not me ? Who is she ?</em>
<em />
<em>Ma sœur </em><em> = my sister</em>
<em />
<em>☺☺☺</em>
