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Keith_Richards [23]
3 years ago
6

If a bowling ball weighing 3,630 g is accelerating down the alley at a rate of 4 m/s2 , then what is the net force applied to th

e bowling ball?
Physics
1 answer:
erastovalidia [21]3 years ago
4 0

Answer:

<h3>The answer is 14.52 N</h3>

Explanation:

The force acting on an object can be found by using the formula

<h3>force = mass × acceleration</h3>

From the question

mass = 3630 g = 3.63 kg

acceleration = 4 m/s²

We have

force = 3.63 × 4

We have the final answer as

<h3>14.52 N</h3>

Hope this helps you

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Gamma rays x rays visible light and radio waves are all types of
bazaltina [42]

Answer:

Electromagnetic waves

Explanation:

Electromagnetic waves are waves that consist of oscillating electric and magnetic fields, that oscillate perpendicularly to each other and perpendicularly to the direction of propagation of the wave (for such a reason, these waves are also called transverse waves).

Electromagnetic waves always travel in a vacuum at the same speed, called speed of light:

c=3.0\cdot 10^8 m/s

and they are classified into 7 different types, according to their frequency. From lowest to highest frequency, we have:

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Therefore, gamma rays, x-rays, visible light and radio waves are all types of electromagnetic waves with different frequencies.

6 0
3 years ago
Determine the index of refraction of glass that is struck by unpolarized light at 53.8 degrees and resulting in a fully polarize
nignag [31]

Answer:

The refractive index of glass, \mu_{g} = 1.367

Solution:

Brewster angle is the special case of incident angle that causes the reflected and refracted rays to be perpendicular to each other or that angle of incident which causes the complete polarization of the reflected ray.

To determine the refractive index of glass:

tan\theta_{P} = \frac{\mu_{g}}{\mu_{a}}                 (1)

where

\mu_{a} = refractive index of glass

\mu_{g} = refractive index of glass

Now, using eqn (1)

tan{53.8^{\circ}} = \frac{\mu_{g}}{1}

\mu_{g} = tan53.8^{\circ}

\mu_{g} = 1.367

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