<1, 2, 3> x (7.6 <-5.3, -4.8, -3.9>) x stands for cross product
What does the above notation mean?
Multiply 7.6 to each component of the velocity vector to obtain the linear momentum vector. Find the cross product of the position vector and the linear momentum vector. That gives you the angular momentum vector.
7.6 * -5.3 = -40.28
7.6 * -4.8 = -36.48
7.6 * -3.9 = -29.64
Cross Multiplication
-40.28 1 = -80.56 - (-36.48)
-36.48 2
-40.28 1 = -120.84 - (-29.64)
-29.64 3
-36.48 2 = -109.44 - (-59.28)
-29.64 3
answer is (-91.2) - (50.16) + 117.04 = -24.32
A wave loses energy as it moves through a medium.
Vx=cos60(4)
x-component of velocity
<span>If you think about it, it makes a right triangle when you combine all the different types of forces together such as v, vx and vy. Then, you can use trigonometry and soh cah toa in order to figure out vx. </span>
Complete question is;
A copper wire has a diameter of 4.00 × 10^(-2) inches and is originally 10.0 ft long. What is the greatest load that can be supported by this wire without exceeding its elastic limit? Use the value of 2.30 × 10⁴ lb/in² for the elastic limit of copper.
Answer:
F_max = 28.9 lbf
Explanation:
Elastic limit is simply the maximum amount of stress that can be applied to the wire before it permanently deform.
Thus;
Elastic limit = Max stress
Formula for max stress is;
Max stress = F_max/A
Thus;
Elastic limit = F_max/A
F_max is maximum load
A is area = πr²
We have diameter; d = 4 × 10^(-2) inches = 0.04 in
Radius; r = d/2 = 0.04/2 = 0.02
Plugging in the relevant values into the elastic limit equation, we have;
2.30 × 10⁴ = F_max/(π × 0.02²)
F_max = 2.30 × 10⁴ × (π × 0.02²)
F_max = 28.9 lbf
