Answer:
The radius, r₂, of the ball that uses one-half the amount of rubber coating used to cover the 16-inch ball is approximately 4.66 inches
Step-by-step explanation:
The dimension of the ball with known radius = 16-inch
The surface area of the ball with 16-inch radius = 4×π×r² = π·D² = π×16² = 804.24772 in.²
Given that the ball uses one-half the rubber material coating used to cover the 16-inch ball, we have the surface area of the ball = 804.24772 in.²/2 = 402.12386 in.²
The radius, r₂ of the new ball is found as follows;
402.12386 in.² = 4×π×r₂²
r₂² = 402.12386 in.² /(4×π) ≈ 32
r₂ = √32 = 4·√2 ≈ 4.66 inches
The radius, r₂, of the ball that uses one-half the amount of rubber coating used to cover the 16-inch ball ≈ 4.66 inches.
288m^3 is what I got, hope it helps!
Answer:
Option C: 15.87 is the correct answer
Step-by-step explanation:
Given
Mean = $47500
SD = $12500
We have to find the probability of having $60000 or more
So,
x = $60000
The z-score will be:
Looking in the z-score table, we get
P(Z<60000) = 0.8413
In order to find the probability P(Z>60000) => 1-P(Z<60000)
= 1-0.8413
=0.1587
Converting into percentage: 0.1587*100 = 15.87%
Hence,
Option C: 15.87 is the correct answer
X= purchase price
Multiply purchase price by sales tax % to equal the amount of sales tax.
(8.75% * x)= $15.75
convert % to decimal (8.75% ÷ 100)
0.0875x= 15.75
divide both sides by 0.0875
x= $180.00 purchase price
ANSWER: The purchase price is $180.00 (to nearest cent).
Hope this helps! :)
Answer:
Step-by-step explanation:
4a:(3)
4b: d=don dx3=
