Answer:
Step-by-step explanation:
The relation is not a function when x -value is same but y- values are different.
#1
#2
- k^2 - 5k = k + 7
- k^2 - 6k = 7
- k^2 - 6k + 9 = 16
- k - 3 = 4 ⇒ k = 7
- k - 3 = -4 ⇒ k = -1
#3
- k^3 - 5k^2 + 3k = -k
- k^3 - 5k^2 + 4k = 0
- k(k^2 - 5k + 4) = 0
- k = 0, k = 1, k = 4
#4
- |k + 1| + 2 = 8
- |k + 1| = 6
- k = 5, k = -7
Answer:
3. Standard deviation is the square root of the variance.
4. Standard deviation is useful because it has the same units as the underlying data.
Step-by-step explanation:
3. In statistics, the dispersion in a given data with respect to its mean distribution can be determined or measured by standard deviation and variance. The standard deviation of a distribution can also be determined as the square root of variance.
4. Standard deviation is measured in the same units as that of the original data. Thus it has the same units as the underlying data.
Answer:20.25
Step-by-step explanation:
If you do 81 divided by 4
I think Im not sure
Answer:
Step-by-step explanation:
