Answer:
Option b. should not be rejected
Step-by-step explanation:
We are given that the contents of a sample of 26 cans of apple juice showed a standard deviation of 0.06 ounces.
We have to test whether the variance of the population is significantly more than 0.003, i.e.;
Null Hypothesis, 
: 
= 
Alternate Hypothesis, 
: 
The test statistics used here for testing variance is;
T.S. = 
~ 
where, s = sample standard deviation = 0.06
n = sample size = 26 cans
So, Test statistics = 
~ 
= 30
So, at 5% level of significance chi square table gives critical value of 37.65 at 25 degree of freedom. Since our test statistics is less than the critical so we have insufficient evidence to reject null hypothesis.
Therefore, we conclude that null hypothesis should not be rejected and variance of population is 0.003.
Answer:
21n² - 28n + 7
Step-by-step explanation:
Each term in the second factor is multiplied by each term in the first factor, that is
3n(7n - 7) - 1(7n - 7) ← distribute both parenthesis
= 21n² - 21n - 7n + 7 ← collect like terms
= 21n² - 28n + 7
Answer:
a
Step-by-step explanation:
the first box is 2 times as small as the the second
Answer:
c. 2
Step-by-step explanation:
Given : X = No. of hours worked
No. of people work for the manager = 50
X = 3, 4 , 5 , 6 , 7, 8
P(X) = 0.1 , ? , 0.14 , 0.3 , 0.36 , 0.06
To Find : No. of people work for four hours
Solution : First understand the fact that sum of all probabilities is equal to 1
So, sum of all values of P(X) = 1
⇒
⇒
⇒
⇒
So, the probability of no. of people worked for 4 hours is 0.04.
⇒P(4)=0.04
Thus , To calculate no. of people work for four hours :
⇒ 2 no. of people work for four hours per shift .
