I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
90 degrees
Step-by-step explanation:
Assuming that this polygon is a square, x would be 90 degrees. In a square, all angles are right angles.
Answer:
Step-by-step explanation:
The point-slope form of an equation of a line:
m - slope
(x₁, y₁) - point
We have the slope m = 2 and the point (-7, 5) → x₁ = -7, y₁ = 5.
Substitute:
Convert to the slope-intercept form (y = mx + b):
<em>use distributive property</em>
<em>add 5 to both sides</em>
Answer:
c
Step-by-step explanation:
Answer:
1) 22
2) 1/98
Step-by-step explanation:
1) Use the equation (x-7)=15.
2) Use the equation 1/14 * 2/14.
- Hope this helps.
