Solution set of inequality-7<3x+2<11, where x is a real number
58, 62, 71, 73, 84, 89, 91, 91, 93, 97, 98, 101,104
Five number summary:
1) minimum = 58
2) 1st quartile = 72
3) median = 91
4) 3rd quartile = 98
5) maximum = 104
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58 72 91 98 104
Answer:
x = 10 cm, y = 5 cm gives a minimum area of 300 cm^2.
Step-by-step explanation:
V= x^2y = 500
Surface area A = x^2 + 4xy.
From the first equation y = 500/x^2
So substituting for y in the equation for the surface area:
A = x^2 + 4x * 500/x^2
A = x^2 + 2000/x
Finding the derivative:
dA/dx = 2x - 2000x^-2
dA/dx = 2x - 2000/x^2
This = 0 for a minimum/maximum value of A, so
2x - 2000/x^2 = 0
2x^3 - 2000 = 0
x^3 = 2000/ 2 = 1000
x = 10
Second derivative is 2 + 4000/x^3
when x = 10 this is positive so x = 10 gives a minimum value of A.
So y = 500/x^2
= 500/100
= 5.
Answer:
3 units
Step-by-step explanation:
Here, The distance between two points is 3 units
<u>-TheUnknownScientist</u>
