1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sineoko [7]
3 years ago
15

Jennifer brought $ 24.75 to the baseball game. She spent $ 12.45 on drinks and snacks. How much money does she have left over?

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
If you do 24.75-12.45 you get 12.30. So there you go!

You might be interested in
Sally paid the following bills rent $450.00 cell phone $37.50 and cable $69.99 how much money did she pay ?
romanna [79]

Answer:

557.49

Step-by-step explanation:

Add the three bills together

450.00

 37.50

 69.99

--------------

557.49

3 0
3 years ago
1) Use Newton's method with the specified initial approximation x1 to find x3, the third approximation to the root of the given
neonofarm [45]

Answer:

Check below, please

Step-by-step explanation:

Hello!

1) In the Newton Method, we'll stop our approximations till the value gets repeated. Like this

x_{1}=2\\x_{2}=2-\frac{f(2)}{f'(2)}=2.5\\x_{3}=2.5-\frac{f(2.5)}{f'(2.5)}\approx 2.4166\\x_{4}=2.4166-\frac{f(2.4166)}{f'(2.4166)}\approx 2.41421\\x_{5}=2.41421-\frac{f(2.41421)}{f'(2.41421)}\approx \mathbf{2.41421}

2)  Looking at the graph, let's pick -1.2 and 3.2 as our approximations since it is a quadratic function. Passing through theses points -1.2 and 3.2 there are tangent lines that can be traced, which are the starting point to get to the roots.

We can rewrite it as: x^2-2x-4=0

x_{1}=-1.1\\x_{2}=-1.1-\frac{f(-1.1)}{f'(-1.1)}=-1.24047\\x_{3}=-1.24047-\frac{f(1.24047)}{f'(1.24047)}\approx -1.23607\\x_{4}=-1.23607-\frac{f(-1.23607)}{f'(-1.23607)}\approx -1.23606\\x_{5}=-1.23606-\frac{f(-1.23606)}{f'(-1.23606)}\approx \mathbf{-1.23606}

As for

x_{1}=3.2\\x_{2}=3.2-\frac{f(3.2)}{f'(3.2)}=3.23636\\x_{3}=3.23636-\frac{f(3.23636)}{f'(3.23636)}\approx 3.23606\\x_{4}=3.23606-\frac{f(3.23606)}{f'(3.23606)}\approx \mathbf{3.23606}\\

3) Rewriting and calculating its derivative. Remember to do it, in radians.

5\cos(x)-x-1=0 \:and f'(x)=-5\sin(x)-1

x_{1}=1\\x_{2}=1-\frac{f(1)}{f'(1)}=1.13471\\x_{3}=1.13471-\frac{f(1.13471)}{f'(1.13471)}\approx 1.13060\\x_{4}=1.13060-\frac{f(1.13060)}{f'(1.13060)}\approx 1.13059\\x_{5}= 1.13059-\frac{f( 1.13059)}{f'( 1.13059)}\approx \mathbf{ 1.13059}

For the second root, let's try -1.5

x_{1}=-1.5\\x_{2}=-1.5-\frac{f(-1.5)}{f'(-1.5)}=-1.71409\\x_{3}=-1.71409-\frac{f(-1.71409)}{f'(-1.71409)}\approx -1.71410\\x_{4}=-1.71410-\frac{f(-1.71410)}{f'(-1.71410)}\approx \mathbf{-1.71410}\\

For x=-3.9, last root.

x_{1}=-3.9\\x_{2}=-3.9-\frac{f(-3.9)}{f'(-3.9)}=-4.06438\\x_{3}=-4.06438-\frac{f(-4.06438)}{f'(-4.06438)}\approx -4.05507\\x_{4}=-4.05507-\frac{f(-4.05507)}{f'(-4.05507)}\approx \mathbf{-4.05507}\\

5) In this case, let's make a little adjustment on the Newton formula to find critical numbers. Remember their relation with 1st and 2nd derivatives.

x_{n+1}=x_{n}-\frac{f'(n)}{f''(n)}

f(x)=x^6-x^4+3x^3-2x

\mathbf{f'(x)=6x^5-4x^3+9x^2-2}

\mathbf{f''(x)=30x^4-12x^2+18x}

For -1.2

x_{1}=-1.2\\x_{2}=-1.2-\frac{f'(-1.2)}{f''(-1.2)}=-1.32611\\x_{3}=-1.32611-\frac{f'(-1.32611)}{f''(-1.32611)}\approx -1.29575\\x_{4}=-1.29575-\frac{f'(-1.29575)}{f''(-4.05507)}\approx -1.29325\\x_{5}= -1.29325-\frac{f'( -1.29325)}{f''( -1.29325)}\approx  -1.29322\\x_{6}= -1.29322-\frac{f'( -1.29322)}{f''( -1.29322)}\approx  \mathbf{-1.29322}\\

For x=0.4

x_{1}=0.4\\x_{2}=0.4\frac{f'(0.4)}{f''(0.4)}=0.52476\\x_{3}=0.52476-\frac{f'(0.52476)}{f''(0.52476)}\approx 0.50823\\x_{4}=0.50823-\frac{f'(0.50823)}{f''(0.50823)}\approx 0.50785\\x_{5}= 0.50785-\frac{f'(0.50785)}{f''(0.50785)}\approx  \mathbf{0.50785}\\

and for x=-0.4

x_{1}=-0.4\\x_{2}=-0.4\frac{f'(-0.4)}{f''(-0.4)}=-0.44375\\x_{3}=-0.44375-\frac{f'(-0.44375)}{f''(-0.44375)}\approx -0.44173\\x_{4}=-0.44173-\frac{f'(-0.44173)}{f''(-0.44173)}\approx \mathbf{-0.44173}\\

These roots (in bold) are the critical numbers

3 0
2 years ago
Solve this quadratic equation<br><img src="https://tex.z-dn.net/?f=3a%20%7B%7D%5E%7B2%7D%20-%204%20%2B%201" id="TexFormula1" tit
ivann1987 [24]

Answer:

1 and 1/3

Step-by-step explanation:

3a² -4a +1 = 0

3a²- 3a - a+ 1= 0

3a(a-1) - (a-1)= 0

(a-1)(3a -1)= 0

a-1= 0 ⇒ a= 1

3a - 1= 0 ⇒ 3a= 1 ⇒ a= 1/3

5 0
2 years ago
Https://skribbl.io/?kX5sVzzk3Iui join skribble.io game
Klio2033 [76]

Answer:

y

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
In Mark's collection of antique bottles, 1 over 2 of of the bottles are dark green. Write three equivalent fractions for 1 over
dalvyx [7]

Answer:

2/4, 3/6, and 4/8

Step-by-step explanation:

Equivalent fractions are made by multiplying the numerator and denominator by the same factor.

For 1/2, you can multiply the top and bottom by 2, 3, or 4 to get 2/4, 3/6, and 4/8 respectively.

3 0
3 years ago
Other questions:
  • In Littletown, the probability that a baseball team goes to the city playoffs is 0.30. the probability that the team goes to the
    7·2 answers
  • Edward deposited $6,000 into a savings account 4 years ago. The simple interest rate is 3%. How much money did Edward earn in in
    10·1 answer
  • Unit price of 1.75 to 10
    5·1 answer
  • Graph the linear function.<br> f(x)=x+2<br> HELP PLEASE
    10·1 answer
  • Helppppppppppppppppp
    5·2 answers
  • 36% of the members in a gym are females. There are 252 female gym members
    6·2 answers
  • If you had 1 cookie and you had three friends how much cookie will they all get?
    10·1 answer
  • Blake must choose between two job offer. Evergreen Landscape will pay him $9.75 hours to mow lawns, but its is a long way from h
    8·1 answer
  • HELP ASAP PLSSSSSSsssssss
    9·1 answer
  • If you have 7ds grand cross friend me and fight me <br><br> hello there here is 40 points :]
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!