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RUDIKE [14]
3 years ago
5

13x – 33 = 7(2x – 4) Solve for x

Mathematics
1 answer:
hichkok12 [17]3 years ago
5 0

Answer:

13x - 33 = 14x - 28 \\ 14x - 13x =  - 33 + 28 \\ x =  - 5

\huge\underline\pink{Hope\:that\:helps}

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4 martians, 3 plutonians and 5 jupiterians are to be seated in a row at an interplanetary conference. How many seating arrangeme
Rudik [331]

we are given

martians =4

plutonians =3

jupiterians=5

so, total number of seats =4+3+5=12

number of seating arrangement for martians is 4!

number of seating arrangement for plutonians is 3!

number of seating arrangement for jupiterians is 5!

total number of seating arrangement is 12!

so, we get

possible seating arrangements are

=\frac{12!}{4!3!5!}

=27720.............Answer

8 0
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A physical science test book has a mass of 2.2 kg what on earth
Molodets [167]

Answer:

what is the ?

Step-by-step explanation:

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7 0
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Pree point sa inyong lahat​
zimovet [89]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
Find the greatest common factor of these three expressions.<br> 18x^2, 42x^4, and 30x^5
DanielleElmas [232]

Answer:I think the answer is 6x because

18= 6x3

42= 6x7

30= 6x5

Step-by-step explanation:

18= 6x3

42= 6x7

30= 6x5 And 6x(3x+7x^3+5x^4) it became 18x^2+42x^4+30x^5

4 0
3 years ago
Help with question 5a
Llana [10]
This is a refreshing question!

We are given that
f(r)=ar+b, and
Sum f(r) =125 for r=1 to 5
Sum f(r) = 475 for r=1 to 10.

and we know, using Gauss's method, that
G(n)=sum (1,2,3.....n) = n(n+1)/2 or
G(n)=n(n+1)/2

Sum f(r) =125 for r=1 to 5
=>
sum=a(sum of 1 to 5) + 5b => G(5)a+5b=125   [G(5)=15]
15a+5b=125 ...................................................(1)

Similarly, Sum f(r) =  475 for r=1 to 10 => G(10)a+5b=475  [G(10)=55]
=>
55a+10b=475.................................................(2)

Solve system of equations (1) and (2)
(2)-2(1)
55-2(15)a=475-2(125) => 25a=225 =>
a=9

Substitute a=9 in 1 => 15(9)+5b=125 => 5b=-10
b=-2

Substitute a and b into f(r), 
f(r)=9r-2
check: sum f(r), r=1,5 = (9-2)+(18-2)+(27-2)+(36-2)+(45-2)=135-10=125 [good]

We define the sum of f(r) for r=1 to n as
S(n)=sum f(r) for r=1 to n = 9(sum 1,2,3....n)-2n = 9n(n+1)/2-2n = 9G(n)-2n
S(n)=9n(n+1)/2-2n
checks:
S(5)=9(15)-2(5)=135-10=125  [good]
S(10)=9(55)-2(10)=495-20=475 [good]

Hence 
(a)
S(n)=sum f(r) for r=1,n
= 9(sum i=1,n)+n(-2)
= 9(n(n+1)/2 -2n
=(9(n^2+n)/2) -2n

(b) sum f(r) for i=8,18
=sum f(r) for i=1,18  -  sum f(r) for i=1,7
=S(18)-S(7)
=(9(18^2-18)/2-2(18))-(9(7^2-7)/2-2(7))
=1503-238
=1265
5 0
3 years ago
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