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3 years ago

Solve (2x-1)/(y)=(w+2)/(2z) for w

Mathematics

1 answer:

zubka84 [21]3 years ago

4 0

Answer:

w= 4xz/y-2

Step-by-step explanation:

2x-1/y=w+2/2z

2x-1x2z=w+2xy

4xz-1=wy+2

4xz-1-2=wy

4xz/y-2=w

w=4xz/y-2

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4 years ago

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3 years ago

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Mila [183]

Answer:

$m\angle H = 44.4\°$ .

Step-by-step explanation:

Given:

In Right Angle Triangle GIH

∠ I = 90°

GI = 7 ....Side opposite to angle H

GH = 10 .... Hypotenuse

To Find:

m∠H = ?

Solution:

In Right Angle Triangle ABC ,Sine Identity,

$sin \ H = \frac{Oppsite\ side\ to\ \angle H}{Hypotenuse}$

Substituting the values we get;

$sin\ H = \frac{7}{10} = 0.7$

Now taking $sin^{-1}$ we get;

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rounding to nearest tenth we get.

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3 years ago

Anyone have the answer for this

sergiy2304 [10]

$\huge\bold{Given:}$

Length of the base = 16 km.

Length of the hypotenuse = 34 km. $\huge\bold{To\:find:}$

✎ The length of the missing leg '' $a$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The length of the missing leg "a" is $\boxed{30\:km}$ .

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

Using Pythagoras theorem, we have

$({perpendicular})^{2} + ({base})^{2} = ({hypotenuse})^{2} \\ ⇢ {a}^{2} + ({16 \: km})^{2} = ({34 \: km})^{2} \\ ⇢ {a}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇢ {a}^{2} = 1156 \: {km}^{2} - 256 \: {km}^{2} \\ ⇢ {a}^{2} = 900 \: {km}^{2} \\ ⇢a \: = \sqrt{900 \: {km}^{2} } \\ ⇢a = \sqrt{30 \times 30 \: {km}^{2} } \\ ⇢a = 30 \: km$

$\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}$

$\huge\bold{To\:verify :}$

$( {30 \: km})^{2} + ({16 \: km})^{2} =( {34 \: km})^{2} \\ ⇝900 \: {km}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\⇝1156 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇝L.H.S.=R. H. S$

Hence verified. ✔

$\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘$

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3 years ago