What is the velocity of an object that has fallen 76 feet

1 answer:

7 0

Ignoring air resistance...

vf^2-vi^2=2gs, where vf is final velocity, vi=initial velocity, g=acceleration due to gravity, and s is the displacement of the object...

For an object being dropped, vi=0, so we have only have final velocity.

v^2=2gs

v=-√(2gs), g≈-32ft/s^2, s=-76

v=-√(2(-32)(-76))

v=-√4864

v≈ -69.74 ft/s (to nearest hundredth of a foot per second)

It's negative because the object is falling, or height is decreasing :P

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