The range is the set of values for y. Since y=|x|, y is always positive and increases without bound as x approaches +oo. Thus the range is:
y≥0 which can also be expressed as y=[0, +oo)
Answer:
first is 2 second is 3
Step-by-step explanation:
f(x)=|x+2|-3 The maximum point is -3 because that is the vertical shift.
f(x)=-|x-2|-3 The minimum point is -3 because that is the vertical shift.
As for the problem in the picture, the vertex is (5,3) because you take the opposite in the absolute value sign and you leave the vertical shift the same, and the graph is shifted 5 units right and 3 units up (Knowing this shift can help you figure out the vertex). The graph opens downward because there is a negative sign in front of it. The maximum is 3 because that is the vertical shift.
To determine the circumference and area of these circles, we must use the proper formulas.
For circumference : 2PiR (or PiD, which Pi = 3.14).
For area: PiR^2
Since we have the radius, let's get to solving!
The first circle (Circle1):
Our radius is 8cm, so let's work for it's circumference. Using our formula, we will multiply 8 by 2 by 3.14.
16 x 3.14 = 50.24.
Circle1's circumference is 50.24cm^2.
Now let's do the area for Circle1.
The radius, 8, squared is (8x8) 64.
64 x 3.14 = 200.96 cm^2.
The area for Circle1 is 200.96cm^2.
Now let's work with Circle2 (second circle).
The radius for that circle is 5cm.
Let's use our circumference formula.
5 x 2 x 3.14 = 10 x 3.14 = 31.4cm^2,
Our circumference for Circle2 is 31.4cm^2.
Now let's do the area for Circle2.
3.14 x 5^2.
25 x 3.14 = 78.5cm^2.
Our area for Circle2 is 78.5.
Let's compare our circumferences and our areas.
Circle1 to Circle 2's Circumference:
50.24:31.4
If we were to divide 50.24 by 31.4 we'd get 1.6.
Circle1 to Circle2's Area: 200.96:78.5.
If we were to divide 200.95 by 78.5 we'd get 2.56.
The circles are NOT similar.
Answer: -79e = -24
Step-by-step explanation:
-23 + - 56e = -79e
This is the furthest we can go in this equation.
