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STatiana [176]
2 years ago
7

A cat weighs​8 1/4​pounds. How many ounces does the cat weigh?

Mathematics
2 answers:
yKpoI14uk [10]2 years ago
6 0

The answer is C 132oz

stepladder [879]2 years ago
5 0

Answer:

132 ounces

Step-by-step explanation:

1 pound = 16 ounces

8 1/4 x 16 = 132

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Can anyone tell me how to solve this 2x+7>-15
denis23 [38]
Answer:
x >-11

Explanation:
2x+7>-15

Subtract 7 from both sides
2x >-15-7

Simplify-15-7 to -22
2x >-22

Divide both sides by 2
22
x > - ___
2

Simplify 22/2 to 11
x >-11
5 0
3 years ago
If 2 limes sell for $0.36, how much will 3 limes cost
dusya [7]
2limes=0.36
we simplify /2
1lime=0.18
times by 3
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7 0
3 years ago
He number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the
denis-greek [22]

The function that represents the number of E.coli bacteria cells per 100 mL of water as t years elapses, and is missing in the question, is:

A(t)=136(1.123)^{4t}

Answer:

   Option A. 59%

Explanation:

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function::

  • A(t)=136(1.123)^{4t}

  • rate=(1.123)^{4t}=(1.123)^4=1.590

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

You can calculate it also using two consecutive values for t. For instance, use t =1 and t = 1

t=1\\\\ A(1)=136(1.123)^4\\\\\\t=2\\ \\ \\A(2)=136(1.123)^8\\ \\ \\A(2)/A(1)=1.123^8/1.1123^4=1.123^4=1.590

6 0
3 years ago
(√2+√3) ^2<br>answer faaaaaaaaaaaaast<br>​
ad-work [718]

Answer:

2.5

Step-by-step explanation:

7 0
3 years ago
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You are 3 years less than twice the age of your sister. Let s be the age (in years) of your sister. Write an expression for your
Lostsunrise [7]

Answer:

2x-3=y

Step-by-step explanation:

let age of sister be x

my age be y

therefore 2x-3=y

4 0
3 years ago
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