Helpppp asap : two non-vertical lines are parallel if they have the same slope and different y-intercepts.

I need the answer as fast as i can get it!

blondinia [14]

Answer:

The answer should be choice D.

HOPE THIS HELPS! :)

7 0

2 years ago

A student has a total of 233 points on three tests. The scores on the first and second tests are the same. The third score excee

skad [1K]

Answer:

Let the scores on the first two test be x

Let score for third test be 14 exceeds second( or first) = x + 14

Total = 233

x + x + (x + 14) = 233

3x + 14 = 233

3x = 219

x = 73

Score of the third test = x + 14 = 73 + 14 = 87

Therefore, the scores are 73, 73, 87

5 0

2 years ago

Cómo resolver sopa de números encontrando resultados de divisiones por ejemplo 436/2

Rzqust [24]

Answer:

Lo resuelves como de costumbre :)

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The exponential decay graph shows the expected depreciation for a new boat, sell g for $3500, over 10 years.

Alisiya [41]

Okay, the exponential function is
$g = a^{x}$
The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes
$g = 3500^{x}$
Let's see at t=2, where the price is g=2000:
$2000 = 3500^{x}$
Take natural logarithm:
$ln 2000 = ln 3500^{x}$
$x*ln 3500 = ln 2000$
$x = \frac{ln 2000}{ln 3500} = 0.93$
So, the difference between t=0 and t=2 is
$x_{t=0} - x_{t=2} = 1 - 0.93 = 0.07$
And then we get the change of x in one year equal to 0.035.
So, the final equation is
$g = 3500^{1-0.035t}$
You can insert any t and see that it is correct, for example t=7

8 0

3 years ago

How many even 5-digit numbers can be formed from the numbers 1, 2, 4, 7, 8 if no digit is repeated in a number? A. 72 B. 120 C.

katovenus [111]

Hello,

Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)

It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24

Thus there are 3*24=72 possibilities.

Answer A

If you do'nt believe run this programm

DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
    FOR i2 = 1 TO 5
        IF i2 <> i1 THEN
            FOR i3 = 1 TO 5
                IF i3 <> i2 AND i3 <> i1 THEN
                    FOR i4 = 1 TO 5
                        IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
                            FOR i5 = 1 TO 5
                                IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
                                    nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
                                    IF nb MOD 2 = 0 THEN
                                        tot = tot + 1
                                    END IF
                                END IF
                            NEXT i5
                        END IF
                    NEXT i4
                END IF
            NEXT i3
        END IF
    NEXT i2
NEXT i1
PRINT "tot="; tot
END

7 0

2 years ago