Answer:
The answer should be choice D.
HOPE THIS HELPS! :)
Answer:
Let the scores on the first two test be x
Let score for third test be 14 exceeds second( or first) = x + 14
Total = 233
x + x + (x + 14) = 233
3x + 14 = 233
3x = 219
x = 73
Score of the third test = x + 14 = 73 + 14 = 87
Therefore, the scores are 73, 73, 87
Answer:
Lo resuelves como de costumbre :)
Step-by-step explanation:
Okay, the exponential function is

The start price of it in t=0 is 3,500, as we can see on the graph. Then, the function becomes

Let's see at t=2, where the price is g=2000:

Take natural logarithm:



So, the difference between t=0 and t=2 is

And then we get the change of x in one year equal to 0.035.
So, the final equation is

You can insert any t and see that it is correct, for example t=7
Hello,
Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)
It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24
Thus there are 3*24=72 possibilities.
Answer A
If you do'nt believe run this programm
DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
FOR i2 = 1 TO 5
IF i2 <> i1 THEN
FOR i3 = 1 TO 5
IF i3 <> i2 AND i3 <> i1 THEN
FOR i4 = 1 TO 5
IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
FOR i5 = 1 TO 5
IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
IF nb MOD 2 = 0 THEN
tot = tot + 1
END IF
END IF
NEXT i5
END IF
NEXT i4
END IF
NEXT i3
END IF
NEXT i2
NEXT i1
PRINT "tot="; tot
END