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olya-2409 [2.1K]
3 years ago
9

Mark spent 733.43 on some cds he purchased 7 cds what was the price of each cds

Mathematics
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

104.77 per cd (why so expensive?)

Explanation:

733.43 ÷ 7 = 104.77

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The perimeter of a rectangular park is 300 feet. The length of the park is 50 feet longer than the width.
bixtya [17]

Answer:

85 feet

Step-by-step explanation:

P=2L+2W where L is the length and W is the width. If the length is 50 feet longer than the width, we can write the expression L=50+W. Substituting into P=2L+2W we get P=2(50+W)+2W=100+2W+2W=100+4W. Since P=300, we can say 300=100+4W. Subtracting 100 from each side we get 200=4W. Dividing each side by 4 gives 50=W. Substituting this into L=50+W gives L=50+35=85. The length is 85 feet.

3 0
2 years ago
A four-pack of 42-ounce ink cartridges sells for $85.99. The expression 42c represents the amount of ink in a number of cartridg
anastassius [24]
C represents the number of four-packs of cartridges because the question says there are 4 pack of 42 ounceink cartridges that sell for 85.99...If you were ever to create an equation with this it would be 42c = 85.99 
And you can plug in 4, 8, or 16 for c and check how much they would cost over all...your welcome, have a great day
7 0
3 years ago
Read 2 more answers
Can someone help me understand this? Because I really don’t understand this at all
Otrada [13]

Answer: I believe it is A OR B

Step-by-step explanation: BECAUSE IF A⇒B AND B⇒C

THEN  ¬A⇒C  I THINK ITS A THO

OR ¬A⇒¬C

7 0
3 years ago
The length of time that an auditor spends reviewing an invoice is approximately normally distributed with a mean of 600 seconds
Bumek [7]
Answer: 11.5% 

Explanation:


Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds. 

Now, we get the z-score for 720 seconds by the following formula:

\text{z-score} =  \frac{x - \mu}{\sigma}

where 

t = \text{time for the auditor to finish his work } = 720 \text{ seconds}
\\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds}
\\ \sigma = \text{standard deviation } = 100 \text{ seconds}

So, the z-score of 720 seconds is given by:

\text{z-score} = \frac{x - \mu}{\sigma}
\\
\\ \text{z-score} = \frac{720 - 600}{100}
\\
\\ \boxed{\text{z-score} = 1.2}

Let

t = time for the auditor to finish his work
z = z-score of time t

Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:

P(t \ \textgreater \  720) 
\\ = P(z \ \textgreater \  1.2)
\\ = 1 - P(z \leq 1.2)
\\ = 1 - 0.885
\\  \boxed{P(t \ \textgreater \  720)  = 0.115}

Hence, there is 11.5% chance that the auditor will spend more than 12 minutes in an invoice. 
8 0
3 years ago
The value of a share of stock in an electronics company increased by 2/3% during one week . IF the value of a share stock was $1
aev [14]
There should be a .94 increase making it be 141.94 at the end of the week.
7 0
2 years ago
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