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Lesechka [4]
2 years ago
11

Easiest way to solve this?

Mathematics
2 answers:
ale4655 [162]2 years ago
6 0

Answer:

add \: all \: and \: divide \: it \: by \: 4 \\  (4 + 6 + 6 + 2) \div 4 \\ 18 \div 4 \\   4.5

mezya [45]2 years ago
6 0

Answer:

Step-by-step explanation:

1. Finding the mean:

\overline{X}=\dfrac{4+6+6+2}{4} =\dfrac{18}{4} =\dfrac{9}{2}=4.5

2 Find the mean of the distance from data to the mean

MAD=\dfrac{|4-\dfrac{9}{2}|+|6-\dfrac{9}{2}|+|6-\dfrac{9}{2}|+|2-\dfrac{9}{2}| }{4} \\\\=\dfrac{|\dfrac{8-9}{2}|+|\dfrac{12-9}{2}|+|\dfrac{12-9}{2}|+|\dfrac{4-9}{2}| }{4} \\\\=\dfrac{|\dfrac{-1}{2}|+|\dfrac{3}{2}|+|\dfrac{3}{2}|+|\dfrac{-5}{2}| }{4} \\\\=\dfrac{\dfrac{1}{2}+\dfrac{3}{2}+\dfrac{3}{2}+\dfrac{5}{2} }{4} \\\\=\dfrac{\dfrac{18}{2}}{4} \\\\=\dfrac{9}{4}\\\\=2.25\\

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Answer:

1  5/12 miles.

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That is 2/3 + 3/4

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Using the piling method which of the following can be constructed from discs alone
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Estimate the quotient for 49 / 311
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An Article a Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the
Sergio039 [100]

Answer:

The estimate is  P__{hat}} \pm E  = 0.37 \pm 0.0348

Step-by-step explanation:

From the question we are told that  

    The sample size is  n =  522

    The sample proportion of students  would like to talk about school is  \r p__{hat}} =  0.37

  Given that the confidence level is  90 % then the level of significance can be mathematically evaluated as

                  \alpha  =  100 - 90

                  \alpha  =  10\%

                  \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is  

               Z_{\frac{\alpha }{2} } =Z_{\frac{0.10}{2} } =  1.645

Generally the margin of error can be mathematically represented as

               E =  Z_{\frac{\alpha }{2} } *  \sqrt{\frac{\r P_{hat}(1- \r P_{hat} )}{n } }

=>            E = 1.645 *  \sqrt{\frac{0.37 (1- 0.37  )}{522 } }

=>             E = 0.0348

Generally the estimate the proportion of all teenagers who want more family discussions about school at 90% confidence level is  

                       P__{hat}} \pm  E

substituting values

                     0.37 \pm 0.0348

5 0
3 years ago
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