Which expressions are equivalent to 4(4a+5)?

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

3 0

B. 4(4a+5)
4 would multiply all what’s in the bracket
16a +20

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What's the answer???

blsea [12.9K]

14/16 or anything like that

3 0

3 years ago

Read 2 more answers

I need help with this problem quick.

KatRina [158]

The absolute value - or distance from zero, is fairly simple to find. Make your final answer positive to find it.

$|\frac{10-7}{4}| = |\frac{3}{4}| = |.75| = .75$

$|\frac{-15+8}{6}| = |-\frac{7}{6}| = |-1.2| = 1.2$

8 0

3 years ago

Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?

Artemon [7]

Answer:

The equation $y=\frac{-x^2-6x+31}{8}$ represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula $d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$ , we find that the distance between (x, y) is

$\sqrt{(x+3)^2+(y-3)^2}$

and the distance between (x, y) and the directrix y = 7 is

$\sqrt{(y-7)^2}$ .

On the parabola, these distances are equal so, we solve for y:

$\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}$