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Shtirlitz [24]
3 years ago
14

A passenger travels from the first floor to the 60th floor, a distance of 210 m in 35 s. what is the elevators speed

Physics
2 answers:
Sati [7]3 years ago
3 0
  • Distance=210m
  • Time=35s

\\ \tt\bull\leadsto Speed=\dfrac{Distance}{Time}

\\ \tt\bull\leadsto Speed=210/35=6m/s

Veseljchak [2.6K]3 years ago
3 0

Answer:

6m per second

Explanation:

Distance=210m

Time=35s

speed=distance/time

speed= 210/35=6ms

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Which of the following is a characteristic of inner planets? (2 points)
Dmitry_Shevchenko [17]
"Inner" planets are usually considered to be Mercury, Venus,
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A).  No.  None of these planets has any substantial amount of hydrogen
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3 0
4 years ago
Read 2 more answers
Suppose that a parallel-plate capacitor has circular plates with radius R = 25 mm and a plate separation of 4.7 mm. Suppose also
ozzi

Answer:

a) B_{max} = 1.784*10^{-12}

Explanation:

Given paraeters are:

R = 25 cm

d = 4.7 mm

f = 60 Hz

V_m = 160 V

a) V = V_msin(2\pi ft)

Where f = 60 Hz and V_m = 160 V

E =V/d= \frac{V_msin(2\pi ft)}{d}

For r = R

A = \pi R^2

Since \Phi_E = EA

\Phi_E=\frac{\pi R^2V_msin(2\pi ft) }{d}

From Ampere's Law:

\int B.ds = \mu_0\epsilon_0\frac{d\Phi_E}{dt} + \mu_0I_{encl} where I_{encl}=0

So at r = R,

B.2\pi R = \mu_0\epsilon_0\frac{d\Phi_E}{dt}\\B.2\pi R = \mu_0\epsilon_0\frac{2\pi^2fR^2V_mcos(2\pi ft)}{d}\\B = \frac{\mu_0\epsilon_0\pi fRV_mcos(2\pi ft)}{d}

For maximum B, cos(2πft) = 1. Hence,

B_{max}=\frac{\mu_0\epsilon_0\pi fRV_m}{d}=\frac{4\pi*10^{-7}*8.85*10^{-12}*\pi*60*0.025*160}{4.7*10^{-3}}=1.784*10^{-12} T

b) From r = 0 to r = R = 0.025 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fR^2V_m}{rd}

From r = R = 0.025 m to r = 0.1 m, by Ampere's Law, the equation will be:

B = \frac{\mu_0\epsilon_0\pi fRV_m}{d}

The plot is given in the attachment.

5 0
4 years ago
Over a span of 6.0 seconds, a car changes it's speed from 89 km/h to 37 km/h. What is its average acceleration in meters per sec
scoundrel [369]

Acceleration = (change in speed) / (time for the change)

change in speed = (speed at the end) - (speed at the beginning)

change in speed = (37 km/hr) - (89 km/hr) = -52 km/hr

Acceleration = (-52 km/hr) / (6 sec)

Acceleration = (-26/3) km/(hr·sec)

Units: (1/hr·sec) · (hr/3600 sec) = 1 / 3600 sec²

(-26/3) km/(hr·sec) = (-26/3) km/(3600 sec²)

= -26,000/(3 · 3600) m/s²

<em>Acceleration = -2.41 m/s²</em>

3 0
4 years ago
The length of a bicycle pedal arm is 0.177 m, and a downward force of 145 N is applied to the pedal by the rider. What is the ma
kramer

Answer:

(a) 19.25 N-m

(b) 25.67 N-m

(c) 0 N-m

Explanation:

Given:

Length of the pedal arm (L) = 0.177 m

Downward force (|\vec{F}|) = 145 N

Magnitude of torque is given by the formula:

T=FL\sin\theta

Where, \theta\to angle\ between\ F\ and\ L

(a)

Given:

\theta=48.6°

Therefore, torque is given as:

T=FL\sin\theta\\\\T=(145\ N)(0.177\ m)(\sin(48.6))\\\\T=19.25\ Nm

Therefore, the torque is 19.25 N-m.

(b)

Given:

\theta=90°

Therefore, torque is given as:

T=FL\sin\theta\\\\T=(145\ N)(0.177\ m)(\sin(90))\\\\T=25.67\ Nm

Therefore, the torque is 25.67 N-m.

(c)

Given:

\theta=180°

Therefore, torque is given as:

T=FL\sin\theta\\\\T=(145\ N)(0.177\ m)(\sin(180))\\\\T=0\ Nm

Therefore, the torque is 0 N-m.

8 0
3 years ago
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