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4 years ago

Which of the following is a characteristic of inner planets? (2 points)

2 answers:

7 0

Earth, Venus, Mercury and Mars are the four inner planets. Scientist call them the 'terrestial planets' because they have solid, rocky surfaces, roughly similar to desert and mountainous areas on Earth.

Dmitry_Shevchenko [17]4 years ago

3 0

"Inner" planets are usually considered to be Mercury, Venus,
Earth, and Mars.

A). No. None of these planets has any substantial amount of hydrogen
or helium in its atmosphere.

B). No. Mercury and Venus have no moons at all, and Earth and Mars
have only three moons total between them.

C). No. Not sure what this means, but the "ground" seems like a pretty fair
land-atmosphere interface, and Venus, Earth, and Mars have a lot of that.

D). Yes. All four of them have it.

You might be interested in

Electric charge is distributed over the disk x2 + y2 ≤ 4 so that the charge density at (x, y) is rho(x, y) = 4x + 4y + 4x2 + 4y2

maw [93]

Answer:

Q=185.84C

Explanation:

We have to take into account the integral

$Q=\int \rho dV$

In this case we have a superficial density in coordinate system.

Hence, we have for R: x2 + y2 ≤ 4

$Q=\int_{-2}^2\int_{-\sqrt{4-x^2}}^{\sqrt{4-x^2}}\rho dydx$

but, for symmetry:

$Q=4\int_0^2\int_0^{\sqrt{4-x^2}}\rho dydx\\\\Q=4\int_0^2\int_0^{\sqrt{4-x^2}}(4x+4y+4x^2+4y^2) dydx\\\\Q=4\int_0^{2}[4x\sqrt{4-x^2}+2(4-x^2)+4x^2\sqrt{4-x^2}+\frac{4}{3}(4-x^2)^{3/2}]dx\\\\Q=4[46.46]=185.84C$

HOPE THIS HELPS!!

8 0

3 years ago

A charge q produces an electric field of strength 4E at a distance of d away. Determine the electric field strength at a distanc

gizmo_the_mogwai [7]

Answer:

c.) 36E

Explanation:

The magnitude of the electric field is given by the expression

$E=k \frac{q}{d^2}$ (1)

where k is the Coulomb's constant, q is the charge that generates the field, and d is the distance from the charge.

In this problem, we have that the magnitude of the field at a distance d is 4E, so we can rewrite the previous equation as

$4E = k\frac{q}{d^2}$

Now we want to determine the electric field at a distance of $d'=\frac{1}{3}d$ away. Substituting into (1), we find

$E' = k \frac{q}{d'^2}=k \frac{q}{(\frac{1}{3}d)^2}=9 k \frac{q}{d^2}$ (2)

We also know that

$4E = k\frac{q}{d^2}$ (3)

So combining (2) with (3), we find a relationship between the original field and the new field:

$E' = 9 \cdot (4E) = 36E$

7 0

3 years ago

Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the melting of ice, and expla

BlackZzzverrR [31]

Melting of ice is an endothermic process, meaning that energy is absorbed. When ice spontaneously melts, ΔH (change in enthalpy) is "positive". ΔS (entropy change) is also positive, because, becoming a liquid, water molecules lose their fixed position in the ice crystal, and become more disorganized. ΔG (free energy of reaction) is negative when a reaction proceeds spontaneously, as it happens in this case. Ice spontaneously melts at temperatures higher than 0°C. However, liquid water also spontaneously freezes at temperatures below 0°C. Therefore the temperature is instrumental in determining which "melting" of ice, or "freezing" of water becomes spontaneous. The whole process is summarized in the Gibbs free energy equation:
ΔG = ΔH – TΔS

4 0

3 years ago

What do all atoms of the same element have in common?

xz_007 [3.2K]

What do all atoms of the same element have in common?

А. atomic mass

B. mass number

C. number of neutrons

D. atomic number

3 0

3 years ago

A plane leaves the airport in Galisteo and flies 170 km at 68.0° east of north; then it changes direction to fly 230 km at 36.0°

luda_lava [24]

Answer:

The direction will be $84.86^\circ$ and the distance 250.75km.

Explanation:

Let's say A is the displacement vector which represents the first 170km and B the one for the next 230km. Then the components of these vector will be:

$A_x=170cos(68^{\circ})\\ A_y=170sin(68^\circ)\\\\B_x=230cos(-36^\circ)\\B_y=230sin(-36^\circ)$