How many different combinations of “on” and “off” are possible with 8 “light bulbs”?
Answer: The total number of combinations of "on" and "off" that are possible with 8 "light bulbs" is 
Therefore, 256 different combinations of “on” and “off” are possible with 8 “light bulbs”
Answer:
Step-by-step explanation:
eq. of circle is x²+y²+2gx+2fy+c=0
center=(-g,-k)
given eq. is x²+y²+4x-8y+11=0
comparing
2gx=4x
g=2
2fy=-8y
f=-4
center=(-2,4)
Answer:
410 student and 436 adult tickets
Step-by-step explanation:
x is the number of student tickets and y is the number of adult tickets sold. we now that a total of 846 tickets were sold so x+y=846=>x=846-y. we also now that their worth was 3 846usd so 3*x+6*y=3846. we substitute x and are left with the following equation:3x+6*(846-x)=3846
5076-3x=3846
3x=1230
x=410
=>y=846-410=436
Answer:
b = 13
Step-by-step explanation:
the value of the discount is a constant, while the total cost of the books is a variable because it depends of the purchase
We can write this equation
5b - 7 = 58
Solve it
1) add 7 at both members
5b -7 + 7 = 58 + 7
5b = 65
2) divide both membera by 5
b = 13
