For the first question asking about the slope 3/4 and y intercept -2 would be (y=0.75x-2) because 3/4=0.75 and the y intercept -2 is b and you’re just placing it into the formula y=Mx+b m=slope b=y intercept.
Answer:
- 1/4 of a pound
- 4/15 of the flat
Step-by-step explanation:
For number 1:
- 3/4 ÷ 3 = 0.25
- 0.25 = 1/4
For number 2:
- 4/5 ÷ 3 = 4/15
I hope this helps!
Answer:
The distance between them after 30 minutes is 6.5 km.
Step-by-step explanation:
Speed = 
Sarah's speed = 6 km/hr = 1.6667 m/s
Emily's speed = 10 km/hr = 2.7778 m/s
The measure of angle between their bearings = 
After 30 minutes (1800 seconds);
distance = speed x time
Sarah would have covered a distance = 1.6667 x 1800
= 3000 m
= 3 km
Emily would have covered a distance = 2.7778 x 1800
= 5000 m
= 5 km
The distance between them, a, can be determined by applying the cosine rule;
=
+
- 2bcCos A
=
+
-2(5000 x 3000) Cos 105
=
+
-2(5000 x 3000) x (-0.2588)
= 2.5 x
+ 9 x
+ 7764000
= 41764000
a = 
= 6462.5073
a = 6462.5 m
The distance between them after 30 minutes is 6.5 km.
Answer:
increase - $2256
price - $50256
Step-by-step explanation:
multiply the percent (in decimal form) by the original cost
48000(0.47)=2256
the increase is $2256
to find the price of it, add the two prices together.
48000+2256=50256
Answer:
a) distance covered by hare d1 = 8t
b) distance covered by tortoise d2 = 5t + 550
c) ∆d = 550 - 3t
Step-by-step explanation:
Given;
Speed of hare u = 8m/s
Speed of tortoise v = 5 m/s
Initial distance of tortoise d0 = 550 m
a) using the equation of motion;
distance covered = speed × time + initial distance
d = vt + d0
For hare;
d0 = 0
Substituting the values;
d1 = 8t + 0
d1 = 8t
b)using the equation of motion;
distance covered = speed × time + initial distance
d2 = vt + d0
For tortoise;
d0 = 550m
Substituting the values;
d2 = 5t + 550
d2 = 5t + 550 m
c) the number of meters the tortoise is ahead of the hare.
∆d = distance covered by tortoise - distance covered by hare
∆d = d2 - d1
Substituting the values;
∆d = (5t + 550) - 8t
∆d = 550 - 3t