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3 years ago

What is the expanded form of 876 million

1 answer:

7 0

First lets write 876 million out:-

876, 000, 000

Now lets write it in expanded form:-

876, 000, 000

800,000,000 + 70,000,000 + 6,000,000 + 0 + 0 + 0 + 0 + 0 + 0 = 876, 000, 000

So, 876 million in expanded form is:-

800,000,000 + 70,000,000 + 6,000,000 + 0 + 0 + 0 + 0 + 0 + 0 =

Hope I helped ya!! xD

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The owner of a local farm sells baskets of fresh tomatoes in the summer time. Each basket is priced according to its mass rounde

elixir [45]

Answer:

4 1/10 kg

Step-by-step explanation:

To find the total mass, we add the mass of the three baskets

1 1/10 + 1 3/10 + 1 7/10

Since they have the same denominator

1 1/10

1 3/10

1 7/10

-------------

3 11/10

Change the improper fraction to a mixed number

11/10 = 1 1/10

3 + 1 1/10

4 1/10

7 0

3 years ago

Brandon is 6 times as old as Cora. In 4 years, Brandon will be only twice as old as

nalin [4]

$C-Cora's\ age\ now\\B-Brandon's\ age\ now\\\\B=6C\ \ \ and\ \ \ B+4=2(C+4)\\\\6C+4=2C+8\\6C-2C=8-4\\4C=4\ \ \ \Rightarrow\ \ \ C=1\ \ \ \Rightarrow\ \ \ \ B=6\cdot1=6\\\\Ans.\ Brandon\ is\ now\ 6\ years.$

4 0

3 years ago

Suppose that 50% of all young adults prefer McDonald's to Burger King when asked to state a preference. A group of 12 young adul

ddd [48]

Answer:

a) 0.194 = 19.4% probability that more than 7 preferred McDonald's

b) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

c) 0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they prefer McDonalds, or they prefer burger king. The probability of an adult prefering McDonalds is independent from other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

50% of all young adults prefer McDonald's to Burger King when asked to state a preference.

This means that $p = 0.5$

12 young adults were randomly selected

This means that $n = 12$

(a) What is the probability that more than 7 preferred McDonald's?

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.121$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.054$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.016$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.003$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.000$

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.121 + 0.054 + 0.016 + 0.003 + 0.000 = 0.194$

0.194 = 19.4% probability that more than 7 preferred McDonald's

(b) What is the probability that between 3 and 7 (inclusive) preferred McDonald's?

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.054$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.121$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.193$

$P(X = 6) = C_{12,6}.(0.5)^{6}.(0.5)^{6} = 0.226$

$P(X = 7) = C_{12,7}.(0.5)^{7}.(0.5)^{5} = 0.193$

$P(3 \leq X \leq 7) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) = 0.054 + 0.121 + 0.193 + 0.226 + 0.193 = 0.787$

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred McDonald's

(c) What is the probability that between 3 and 7 (inclusive) preferred Burger King?

Since $p = 1-p = 0.5$ , this is the same as b) above.

0.787 = 78.7% probability that between 3 and 7 (inclusive) preferred Burger King

7 0

3 years ago

12 subtracted from a number equals 25 find the number

belka [17]

Answer: 12-n=25

-n=25-12

-n=13

Step-by-step explanation:

6 0

3 years ago

5^2+b^2=13^2 steps to solve

Ket [755]

Answer:

b=12 or b=−12

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers