Answer:
here is answer
Step-by-step explanation:
n(AUB) = n(A) + n(B) - n(AnB )
= 240 + 160 - n(A n B)
= 400 - n(AnB )
Since n(AnB) 20, so n(AUB) S 400
But n(U) = 360, so n(A U B)* 360
.. the maximum value of n(AUB) = 360.
When n(A U B) is maximum, n(AnB) will be minimum.
.. min. value of n(An B)
= n(A) + n(B) - Max, value of n(AUB)
= 240 - 160 - 360 = 40
Again, n(
A B) will be maximum when B C A.
..the max. value of n(
A B) = n(B) = 160
Answer:
4
Step-by-step explanation:
4 × 8 = 32
Divide each side by 8
4 × 8 /8= 32/8
4 = 32/8
A zero, or a solution of the quadratic function is c) x = 6 1/3
Write -54x as a difference
9x^2 + 3x - 57x - 19
Factor 3x out
{ 9x^2 + 3x } - 57x - 19
3x (3x + 1)
Factor -19 out
3x (3x + 1) -19 (3x + 1)
Group the equations
( 3x - 19 ) ( 3x + 1 )
Solve for the zeroes
(3x+1) = 0
-1 -1
3x = -1
3x / 3 = x
-1 / 3 = -1/3
x = - 1/3
(3x - 19) = 0
+19 +19
3x = 19
3x / 3 = x
19 / 3 = 6 1/3
x = 6 1/3
Answer:
640 m
Step-by-step explanation:
We can consider 4 seconds to be 1 time unit. Then 8 more seconds is 2 more time units, for a total of 3 time units.
The distance is proportional to the square of the number of time units. After 1 time unit, the distance is 1² × 80 m. Then after 3 time units, the distance will be 3² × 80 m = 720 m.
In the additional 2 time units (8 seconds), the ball dropped an additional
... (720 -80) m = 640 m
_____
<em>Alternate solution</em>
You can write the equation for the proportionality and find the constant that goes into it. If we use seconds (not 4-second intervals) as the time unit, then we can say ...
... d = kt²
Filling in the information related to the first 4 seconds, we have ...
... 80 = k(4)²
... 80/16 = k = 5
Then the distance equation becomes ...
... d = 5t²
After 12 seconds (the first 4 plus the next 8), the distance will be ...
... d = 5×12² = 5×144 = 720 . . . meters
That is, the ball dropped an additional 720 -80 = 640 meters in the 12 -4 = 8 seconds after the first data point.
30/-6 equals 5. You’re welcome
