Ok so R=alfonso's rate
w=wind rate=4
d=rt
with wind rate is R+4
agaoins wind rate is R-4
with wind distance is 34
against is 18 miles
time is same
34=(r+4)t
18=(r-4)t
34=(r+4)t
divide both sides by (r+4)
34/(r+4)=t
18=(r-4)t
divide both sides by (r-4)
18/(r-4)=t
18/(r-4)=t
34/(r+4)=t
set equal to each other
18/(r-4)=34/(r+4)
multiply both sides by (r-4)(r+4)
18(r+4)=34(r-4)
distribute
18r+72=34r-136
subtract 18r from both sides
72=16r-136
add 136 to both sides
208=16r
divide both sides by 16
13mph
answer is 13mph with no wind
Answer:
The big pump moves 22 more gallons in 10mins
Step-by-step explanation:
The total the big pump moves is 30 gallons in 10mins because 3x10 = 30
The small pump moves 8 gallons in 10mins becuase 4x2= 8
Its asking for how many more so 30 - 8 = 22 More gallons
Answer:
A: 4:5
Step-by-step explanation:
You can simplify 20:25 and get 4:5.
Hope this helps!
Answer:
13.5
Step-by-step explanation:
area: 1/2*[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
Answer:
First you right the division as a fraction
1/5x=5
then mutiply both sides of the equation by 5
x=25
Step-by-step explanation:
