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fiasKO [112]
3 years ago
8

There are two 5th grade classes at Jones Elementary School. Mrs. Roberts has 17 girls and 18 boys in her class. Mr. Simpson has

16 boys and 19 girls in his class. If a 5th grade student is selected at random, what is the probability that it will be a girl? Give the answer as a fraction in simplest form.
Mathematics
2 answers:
snow_lady [41]3 years ago
4 0

Answer:

10/17

Step-by-step explanation:

you add all of the girls then you and all of the boys. There are 20 girls and there are 34 boys. You would divide both of them by two. then the fraction that you will get is 10/ 17.

boyakko [2]3 years ago
3 0

Answer:

The chance of a girl being picked is an 18/35 chance.

Step-by-step explanation:

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Romashka-Z-Leto [24]

Answer:

The y intercept is 3

(0,3)

Step-by-step explanation:

4x+2y=6

To find the y intercept, set x =0 and solve for y

4(0) +2y = 6

0+2y = 6

Divide by 2

2y/2 = 6/2

y =3

The y intercept is 3

(0,3)

6 0
3 years ago
What does 144 =to for a squared
Dafna11 [192]
12 *12 = 144

Therefore 12^2 = 144
5 0
3 years ago
Read 2 more answers
A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando
kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

          p = probability of success

          x = no. of successful trials

          q = probability of failure = 1-p

we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

P(X≥1) = P(X=1) + P(X=2) + P(X=3) + P(X=4)

A shorter method to do this is to use the total probability theorem:

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ (0.02)⁰(0.98)⁴⁻⁰

          = 1 - (0.98)⁴

          = 1 - 0.9224

P(X≥1) = 0.0776

4 0
3 years ago
The average reading score on certain tests is given by y = 0.153x + 255.4, where x is the number of years past 1970. In what yea
nirvana33 [79]

Average reading score is given by the expression,

        y = 0.153x + 255.4

Here, x in the number of years past 1970.

To find the year in which the average reading score is 259.378, substitute the value of 'y' in the given expression.

y = 0.153x + 255.4

259.378 = 0.153(x) + 255.4

0.153x = 259.378 - 255.4

0.153x = 3.978

x = \frac{3.978}{0.153}

x = 26

That means given average reading score 259.378 will be 26 years after 1970.

       Therefore, 1996 is the year in which the average reading score will be 259.378.

Learn more,

brainly.com/question/2883790

3 0
2 years ago
Is y=4x+3 and 4x+y=3 parallel or perpendicular or neither?
Sedbober [7]
Neither of the equations are parallel or perpendicular
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