Answer:
Option C .
Step-by-step explanation:
We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>


Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>



Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>



<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>p</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>C</u><u> </u><u>i</u><u>s</u><u> </u><u>c</u><u>o</u><u>r</u><u>r</u><u>e</u><u>c</u><u>t</u><u> </u><u>.</u>
Answer:
p = -1 q = -4
Step-by-step explanation:
a system of eq and solve for p and q ??? can do :)
Eq. 1) 8p + 2q = - 16
Eq. 2) 2p - q = 2
use Eq .2 and solve for q
2p - 2 = q
plug into Eq.1 with q
8p +2(2p - 2) = - 16
8p +4p -4 = -16
12p = - 12
p = -1
plug -1 into Eq. 1 for p and solve for q
8(-1) + 2q = - 16
-8 + 2q = - 16
2q = -8
q = -4
Assuming the price of the pool does not change, then
Additional interest required is 4500-3750=750
using
I=Pit, we set up equation
750=3750*0.055*t
Solve for t
t=750/(3750*0.055)=3.64 years.
So will need to wait 3.64 years, or rounded up to 4 years.
Answer:
sure
Step-by-step explanation: