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Alex_Xolod [135]
3 years ago
10

Berniece solved the following equation:

Mathematics
1 answer:
aniked [119]3 years ago
5 0

Answer:

Step 4.

Step-by-step explanation:

To isolate the x variable, she subtracts 8 from both sides making it another subtraction property of equality justification.

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Please help with this equation problem. Find y and show your work- will give brainliest
Nikolay [14]

Answer: 8x=-2

The steps are in the photo below

3 0
3 years ago
A footbridge is 5 feet wide and is built with wood planks that are 6 inches wide. How many planks wide is the path?
Ede4ka [16]

Here we have to know the conversion between feet and inches.

1 Feet = 12 inches (This is given and is to be known)

So the 5 feet wide footbridge when converted to inches would be about 5*12 = 60 inches

The width of the footbridge in inches = 60 inches

Each wooden plank is 6 inches,

So the number of wooden planks that are required to build the foot bridge of 60 inches = 60/6 = 10 planks

Hence, the path path is 10 planks wide

7 0
3 years ago
translate this into an equation, use n for the number: "the different of 3 times a number and 6 is twice the number."
natali 33 [55]

Answer:

6

Step-by-step explanation:

6 * 3 = 18

18 - 6 = 12

12 is twice of 6, the number

4 0
3 years ago
Can anyone help solve this equation?
koban [17]

Answer:

13

Step-by-step explanation:

3 x 3 = 9

7 + 3 = 10

7 + ? = 3 + 7 + 3 + 7

7 + ? = 20

? = 13

3 0
3 years ago
Read 2 more answers
The length width and height of a rectangular solid are 8,4,1 respectively what is the length of the longest line segment whose e
LUCKY_DIMON [66]

Answer:

9 units

Step-by-step explanation:

Given

Length = 8

Width = 4

Height = 1

Required

Determine the length of the longest segment

To do this, we use:

Longest = \sqrt{Length^2 + Width^2 + Height^2}

So, we have:

Longest = \sqrt{8^2 + 4^2 + 1^2}

Longest = \sqrt{64 + 16 + 1}

Longest = \sqrt{81}

Take positive square root

Longest = 9

<em>Hence, the length of the longest segment is 9 units</em>

3 0
3 years ago
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