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mr_godi [17]
3 years ago
5

PLZ HELP ASAP IF U ABSOLUTELY KNOW IM TIMED THX Which statement is true

Mathematics
2 answers:
nadya68 [22]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Kipish [7]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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3 years ago
John borrows $6.50 from his friends to pay for snacks, and $11.75 from his sister to go to the movies how much money does he nee
Nina [5.8K]

John has borrowed $6.50 from his friends and $11.75 from his sister. To find how much money he needs to repay you can just add up the amount of money he has borrowed.

Make an equation to solve for this, where x = amount of money John needs to repay. Make the amount of money John borrowed add up to x. Your equation should look like:

$6.50 + $11.75 = x

Combine like terms (add 6.50 and 11.75).

$18.25 = x

After solving the equation, you have figured out that John need to repay $18.25 in total.

6 0
3 years ago
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!!!!!(Help me please I will give brainliest)!!!!!<br><br> Put the fraction in its simplest form plz
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I’ve attached my work below
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8 0
2 years ago
You play two games against the same opponent. The probability you win the first game is 0.4. If you win the first game, the prob
Ilia_Sergeevich [38]

Answer:

a) No

b) 42%

c) 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

e) 0.62

Step-by-step explanation:

a) No, the two games are not independent because the the probability you win the second game is dependent on the probability that you win or lose the second game.

b) P(lose first game) = 1 - P(win first game) = 1 - 0.4 = 0.6

P(lose second game) = 1 - P(win second game) = 1 - 0.3 = 0.7

P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

c)   P(win first game)  = 0.4

P(win second game) = 0.2

P(win both games) = P(win first game)  × P(win second game) = 0.4 × 0.2 = 0.08 = 8%

d) X               0                 1                2

   P(X)           42%            50%         8%

P(X = 0)  =  P(lose both games) = P(lose first game)  × P(lose second game) = 0.6 × 0.7 = 0.42 = 42%

P(X = 1) = [ P(lose first game)  × P(win second game)] + [ P(win first game)  × P(lose second game)] = ( 0.6 × 0.3) + (0.4 × 0.8) = 0.18 + 0.32 = 0.5 = 50%

e) The expected value  \mu=\Sigma}xP(x)= (0*0.42)+(1*0.5)+(2*0.08)=0.66

f) Variance \sigma^2=\Sigma(x-\mu^2)p(x)= (0-0.66)^2*0.42+ (1-0.66)^2*0.5+ (2-0.66)^2*0.08=0.3844

Standard deviation \sigma=\sqrt{variance} = \sqrt{0.3844}=0.62

8 0
3 years ago
What number would you add to both sides of x2 + 7x = 4 to complete the square?
tamaranim1 [39]

Answer: (7/2)^2

Step-by-step explanation:

5 0
3 years ago
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