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3 years ago

(01.02)

Mathematics

1 answer:

Bas_tet [7]3 years ago

8 0

Step-by-step explanation:

it is option c. you interchange the value with y and take inverse.

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A rectangle with a width of x + 2 and a length of 8, has the same

MariettaO [177]

I would say wow in very good job to the song you wrote the song PA would be six equal 12+24 perimeter of X equals force not two equals four I hope this helps

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3 years ago

Using 10 grams of a 15% boric acid ointment, the pharmacist will manufacture a 12% ointment. how many milligrams of diluent is r

yan [13]

Use equation C1M1+C2M2=CM
C1=15%, M1=10000 mg (starting ointment)
C2=0% M2=to be found (diluent)
C=12% M=M1+M2 (product)

Solve for M2
0.15*10000+0*M2 = 0.12(10000+M2)
M2=(0.15-0.12)*10000/0.12=2500 mg

Answer: 2500 mg of diluent is required.

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4 years ago

Add the following numbers together: 80, 85, 90, 65, 80, 60

marysya [2.9K]

Answer:

Adding all the numbers together results in 460

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4 years ago

Read 2 more answers

You perform a X2 goodness-of-fit test to see if the number of birthdays occurring each month matches the expected number (assumi

aivan3 [116]

Answer:

$p_v = P(\chi^2_{11} >20.5)=0.0389$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(20.5,11,TRUE)"

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

We need to conduct a chi square test in order to check the following hypothesis:

H0: Each month is equally likely to be the birth month for any given individual

H1: Each month is NOT equally likely to be the birth month for any given individual

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

After calculate the statistic we got $\chi^2 = 20.5$

Now we can calculate the degrees of freedom for the statistic given by:

$df=categories-1=12-1=11$

And we have categories =12 since we have 12 months in a year

And we can calculate the p value given by:

$p_v = P(\chi^2_{11} >20.5)=0.0389$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(20.5,11,TRUE)"

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3 years ago

Jill has a gift certificate for a movie rental. Each time she rents a movie, $6 is deducted from her gift certificate balance. I

emmasim [6.3K]

I think it is or d becuase it depends on witch place they want to have the varible

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3 years ago