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Zepler [3.9K]
2 years ago
7

Anyone who do bug bounty hunting ?​

Computers and Technology
1 answer:
olchik [2.2K]2 years ago
5 0

Answer:

No

Explanation:

I do not because it's working with skilled security researchers from all over the world is the key to identifying

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A perfect binary tree is a complete binary tree with all levels fully filled. Add a method in the BST class to return true if th
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Answer:

class BST {

static class Node

{

int val;

Node left, right;

}

static boolean checkPerfectBT(Node node, int h, int d)

{

if (node == null)

return true;

 

if (node.left == null && node.right == null)

{

if(h==d+1)

return true;

else

return false;

}

 

if (node.left == null || node.right== null)

return false;

 

return checkPerfectBT(node.left, h, d+1) && checkPerfectBT(node.right, h, d+1);

}

static int height(Node node)

{

int dep = 0;

while (node != null)

{

node = node.right;

dep=dep+1;

}

return dep;

}

static boolean isPerfectBT(Node node)

{

int h = height(node);

return checkPerfectBT(node, h, 0);

}

 

static Node addNode(int x)

{

Node node = new Node();

node.val= x;

node.right = null;

node.left = null;

return node;

}

public static void main(String args[])

{

int i,j,k;

Node node= null;

node = addNode(34);

node.left = addNode(2);

node.right = addNode(322);

 

node.left.left = addNode(21);

node.left.right = addNode(23);

node.right.left = addNode(37);

node.right.right = addNode(54);

 

if (isPerfectBT(node) == true)

System.out.println("This is a Perfect Binary tree");

else

System.out.println("This is Not a perfect Binary Tree");

}

}

Explanation:

  • Calculate the depth of BST by using a while loop until it reaches a null value.
  • In the addNode method, make an object of Node class.
  • In the main method, pass the values to addNode method.
  • Finally display the relevant message to show if it's Perfect or not.
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Netstat -r

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Which soft skill involves the ability to produce ideas that will give an organization an advantage with respect to other organiz
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B.  Strategic thinking

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5 0
3 years ago
Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static
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Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}

7 0
3 years ago
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