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trasher [3.6K]
3 years ago
5

Pleas help me buddy pleeeas

Mathematics
1 answer:
o-na [289]3 years ago
7 0
1. 8a^7b^6

2.5/2 a-³b^4

3.4/3 a-²b³
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23)
Kaylis [27]

Answer:

90 degrees

Step-by-step explanation:

Step 1: State what is known

Notice that the 2 lines cut the square in half and create 4 congruant triangles.  We know a full circle is 360 degrees and the intersection is a perfect circle formed by 4 angles.  We can find the angle AEB by dividing 360 by 4 which gives you 90 degrees

8 0
2 years ago
The average of 5 numbers is 33. If the average of first 2 numbers is 35 and that of last 2 is 31, then find the 3rd number.
-BARSIC- [3]
The answer is c. 33.
3 0
3 years ago
Read 2 more answers
If 9 oz make 10 servings how many oz do I need to make 13 servings
Luden [163]
9/10 = x/13. Solve for x. X = 11.7.
Your answer would be 11.7oz. Hope this helps
4 0
3 years ago
15x+8=6x+2<br><br> Find X please I beg you I have to feed my kids
Rzqust [24]

Answer:

15x+8=6x+2\\9x+8=2\\9x=-6\\x=-6/9 or -2/3\\Hope this helps plz hit the crown :D

4 0
3 years ago
Read 2 more answers
Suppose that you are an elementary school teacher and you are evaluating the reading levels of your students. You find an indivi
aleksklad [387]

Answer:

The child's reading level is at the 3.4th percentile.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

You do some research and determine that the reading rates for their grade level are normally distributed with a mean of 90 words per minute and a standard deviation of 24 words per minute.

This means that \mu = 90, \sigma = 24

You find an individual that reads 46.4 word per minute. At what percentile is the child's reading level?

The percentile is the p-value of Z when X = 46.4, multiplied by 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.4 - 90}{24}

Z = -1.82

Z = -1.82 has a p-value of 0.034.

0.034*100 = 3.4

The child's reading level is at the 3.4th percentile.

6 0
3 years ago
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