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NNADVOKAT [17]
2 years ago
11

Type the slope intercept equation of the line that passes through the points (3, -2) and (6, 4)

Mathematics
1 answer:
Salsk061 [2.6K]2 years ago
8 0
0 is the awnser too this one
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Expand and Simplify 2(3x - 1) - 4(2x +3) please
Lina20 [59]

Answer:

-2x-14

Step-by-step explanation:

7 0
2 years ago
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Find the absolute maximum and minimum values of the following function on the given interval. If there are multiple points in a
Bond [772]

f(x)=3\sin x+3\cos x\implies f'(x)=3\cos x-3\sin x

f has critical points where f'=0:

3\cos x-3\sin x=0\implies\cos x=\sin x\implies\tan x=1\implies x=\pm\dfrac\pi4+2n\pi

where n is any integer. We get solutions in the interval \left[0,\frac\pi3\right] for n=0, for which x=\frac\pi4.

At this critical point, we have f\left(\frac\pi4\right)=3\sqrt2\approx4.243.

At the endpoints of the given interval, we have f(0)=3 and f\left(\frac\pi3\right)=\frac{3+3\sqrt3}2\approx4.098.

So we have the extreme values

\max\limits_{x\in\left[0,\frac\pi3\right]}f=3\sqrt2

\min\limits_{x\in\left[0,\frac\pi3\right]}f=3

8 0
3 years ago
Twenty percent of the students at Drew's school walk to school. There are 300 students in Drew's school. How many students walk
swat32

20% of 300 equals 60

7 0
2 years ago
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Please , can someone answer thisss TmT
Tems11 [23]

Answer:

7

Step-by-step explanation:

We have that x1=−1, y1=5, x2=3, y2=7.

Plug the given values into the formula for a slope: m=7−(5)3−(−1)=12.

Now, the y-intercept is b=y1−mx1 (or b=y2−mx2, the result is the same).

b=5−(12)(−1)=112

Finally, the equation of the line can be written in the form y=b+mx:

y=112+x2

ANSWER

5 0
3 years ago
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Find the fifth term in the sequence that is defined as follows an=n2+2
Angelina_Jolie [31]
A(5) = 2 + 5^2 = 2 + 25 = 27
Step-by-step explanation:
This sequence is defined as a(n) = 2 + n^2.
Thus, a(1) = 2 + 1^2 = 2 + 1 = 3
Then a(5) = 2 + 5^2 = 2 + 25 = 27
8 0
2 years ago
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