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Pavlova-9 [17]
3 years ago
7

You want to put $2,500 in a simple interest account.It has a 4% annual interest rate.How long will it take you to earn $200 in i

nterest?
Mathematics
1 answer:
prohojiy [21]3 years ago
7 0
It will take 2 years.

Year 1 :
4% 2.5k = 2.5k/100 × 4 = $100 in interest

$2.5k + $0.1k = $2.6k

Year 2 :
4% 2.6k = 2.6k/100 × 4 = $104 in interest

$100 + $104 = $204 > $200

There may be a simpler way to solve this using a formula for example, but I just solved this step by step. Please feel free to ask if you have any questions
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It takes Peter 4 hours to walk 12 miles.If he continues to walk at the same rate, how long will it take him to walk:
blondinia [14]

Answer:

a]2.3 hrs

b]3.6hrs

Step-by-step explanation:

4hrs = 12 miles

x       =  7miles

4 x 7=28/12=2.3

4 x 11=44/12=3.6hrs

6 0
4 years ago
Read 2 more answers
Solve. Write answer in simplest form.<br> 7 - 2/5 =
Arlecino [84]

Answer:

6 3/5

Step-by-step explanation:

7 - 2/5 = 6 3/5

Sorry I can’t really explain this. It just comes into my head

3 0
2 years ago
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One ticket costs $15.45. Three tickets would cost?
Troyanec [42]
46.35 is the answer
8 0
3 years ago
Help me please...........?
Makovka662 [10]
189 inches is 15.75 feet

16 ft - 15.75 ft = 0.25 ft

0.25ft = 3 inches

He must vault 3 inches higher
4 0
3 years ago
PLEASE HELP!!! WILL GIVE BRAINLIEST!!!
777dan777 [17]

Answer: (2,2) and (-5,16)

Step-by-step explanation:

Here we have both Line (Linear Function) and Parabola (Quadratic Function)

So I am gonna write these equations here,

y=x^2+x-4\\y=-2x+6

The first equation has Parabola graph (Since it's second degree.)

and the second equation has line graph.

To find the intersection, you have to substitute either -2x+6 in first equation (Quadratic) or x^2+x-4 in second equation (Linear)

For me, I am going to substitute x^2+x-4 in y=-2x+6.

x^2+x-4=-2x+6

Now solve the equation and find the value of x.

Since it's Quadratic Equation (Because there's x^2) I'd move -2x+6 to the left side.

x^2+x-4+2x-6=0 Finish things here (Subtract and Addition)

x^2+3x-10=0 What two numbers multiply to 10? Find the factors of 10, that are [1 and 10] and [2 and 5]

Now think about it, do you think that if 1 and 10 subtract or even addition, do you think that it'd be 3? No, of course not.

So 2 and 5 is right.

(x-2)(x+5)=0 (5-2 = 3) and (5*(-2) = -10)

Then we get both x, x=2,-5

However, this is not it. You have to substitute both x in Linear Equation.

Substitute x = 2 in y=-2x+6

y=-2(2)+6\\y=-4+6\\y=2

Order = (2,2)

Then substitute x = -5 in y=-2x+6

y=-2(-5)+6\\y=10+6\\y=16

Order = (-5,16)

So the intersections are both (2,2) and (-5,16) as shown in graph below.

4 0
4 years ago
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